Search: id:A001204 Results 1-1 of 1 results found. %I A001204 M4322 N1811 %S A001204 7,2,1,1,3,18,5,1,1,6,30,8,1,1,9,42,11,1,1,12,54,14,1,1,15,66,17,1,1, %T A001204 18,78,20,1,1,21,90,23,1,1,24,102,26,1,1,27,114,29,1,1,30,126,32,1,1, %U A001204 33,138,35,1,1,36,150,38,1,1,39,162,41,1,1,42,174,44,1,1,45,186,47,1,1 %N A001204 Continued fraction for e^2. %D A001204 N. J. A. Sloane and Simon Plouffe, The Encyclopedia of Integer Sequences, Academic Press, 1995 (includes this sequence). %D A001204 N. J. A. Sloane, A Handbook of Integer Sequences, Academic Press, 1973 (includes this sequence). %D A001204 O. Perron, Die Lehre von den Kettenbr\"{u}chen, 2nd ed., Teubner, Leipzig, 1929, p. 138. %H A001204 Harry J. Smith, Table of n, a(n) for n=0,...,20000 %H A001204 G. Xiao, Contfrac %H A001204 Index entries for continued fractions for constants %H A001204 K. Matthews, Finding the continued fraction of e^(l/m) %F A001204 G.f.: (x^10-x^8-x^7+x^6+4x^5+3x^4+x^3+x^2+2x+7)/(x^5-1)^2. - Ralf Stephan (ralf(AT)ark.in-berlin.de), Mar 23 2003 %F A001204 For n>0, a(5n)=12n+6, a(5n+1)=3n+2, a(5n+2)=a(5n+3)=1 and a(5n+4)=3n+3. - Dean Hickerson (dean.hickerson(AT)yahoo.com), Mar 25 2003 %e A001204 7.389056098930650227230427460... = 7 + 1/(2 + 1/(1 + 1/(1 + 1/(3 + ...)))) [From Harry J. Smith (hjsmithh(AT)sbcglobal.net), Apr 30 2009] %t A001204 ContinuedFraction[ E^2, 100] %o A001204 (PARI) contfrac(exp(2)) %o A001204 (PARI) { allocatemem(932245000); default(realprecision, 95000); x=contfrac(exp(2)); for (n=1, 20001, write("b001204.txt", n-1, " ", x[n])); } [From Harry J. Smith (hjsmithh(AT)sbcglobal.net), Apr 30 2009] %Y A001204 Sequence in context: A153589 A010505 A020844 this_sequence A021585 A103713 A089129 %Y A001204 Adjacent sequences: A001201 A001202 A001203 this_sequence A001205 A001206 A001207 %K A001204 easy,nonn,cofr,nice %O A001204 0,1 %A A001204 N. J. A. Sloane (njas(AT)research.att.com). %E A001204 More terms from Robert G. Wilson v (rgwv(AT)rgwv.com), Dec 07 2000 Search completed in 0.001 seconds