Search: id:A001611 Results 1-1 of 1 results found. %I A001611 M0288 N0103 %S A001611 1,2,2,3,4,6,9,14,22,35,56,90,145,234,378,611,988,1598,2585,4182, %T A001611 6766,10947,17712,28658,46369,75026,121394,196419,317812,514230, %U A001611 832041,1346270,2178310,3524579,5702888,9227466,14930353,24157818 %N A001611 Fibonacci numbers (A000045) + 1. %C A001611 a(n) = Fibonacci(n) + 1. %C A001611 a(0) = 1, a(1) = 2 then the largest number such that a triangle is constructible with three successive terms as sides. - Amarnath Murthy (amarnath_murthy(AT)yahoo.com), Jun 03 2003 %C A001611 a(n+2)=A^(n)B(1), n>=0, with compositions of Wythoff's complementary A(n):=A000201(n) and B(n)=A001950(n) sequences. See the W. Lang link under A135817 for the Wythoff representation of numbers (with A as 1 and B as 0 and the argument 1 omitted). E.g. 2=`0`, 3=`10`, 4=`110`, 6=`1110`,..., in Wythoff code. %D A001611 N. J. A. Sloane and Simon Plouffe, The Encyclopedia of Integer Sequences, Academic Press, 1995 (includes this sequence). %D A001611 N. J. A. Sloane, A Handbook of Integer Sequences, Academic Press, 1973 (includes this sequence). %D A001611 G. Everest, A. van der Poorten, I. Shparlinski and T. Ward, Recurrence Sequences, Amer. Math. Soc., 2003; see esp. p. 255. %D A001611 D. Jarden, Recurring Sequences. Riveon Lematematika, Jerusalem, 1966. %D A001611 N. S. Mendelsohn, Permutations with restricted displacement, Canad. Math. Bull., 4 (1961), 29-38. %H A001611 INRIA Algorithms Project, Encyclopedia of Combinatorial Structures 402 %H A001611 S. Plouffe, Approximations de S\'{e}ries G\'{e}n\'{e}ratrices et Quelques Conjectures, Dissertation, Universit\'{e} du Qu\'{e}bec \`{a} Montr\'{e}al, 1992. %H A001611 S. Plouffe, 1031 Generating Functions and Conjectures, Universit\'{e} du Qu\'{e}bec \`{a} Montr\'{e}al, 1992. %F A001611 G.f.: (1-2*x^2)/(1-2*x+x^3). %F A001611 a(0) = 1, a(1) = 2, a(n) = a(n - 2) + a(n - 1) - 1. %F A001611 Fibonacci(4n) + 1 = Fibonacci(2n-1)*Lucas(2n+1); Fibonacci(4n+1) + 1 = Fibonacci(2n+1)*Lucas(2n); Fibonacci(4n+2) + 1 = Fibonacci(2n+2)*Lucas(2n); Fibonacci(4n+3) + 1 = Fibonacci(2n+1)*Lucas(2n+2). - R. K. Guy, Feb 27, 2003. %F A001611 a(n) = 2a(n-1) - a(n-3) - Tanya Khovanova (tanyakh(AT)yahoo.com), Jul 13 2007 %F A001611 a(n)=(Fibonacci(n)+Fibonacci(n+3)+2)/2 - Zerinvary Lajos (zerinvarylajos(AT)yahoo.com), Feb 01 2008 %p A001611 A001611:=-(-1+2*z**2)/(z-1)/(z**2+z-1); [S. Plouffe in his 1992 dissertation.] %p A001611 with(combinat): seq((fibonacci(n)+fibonacci(n+3)+2)/2, n=-2..35); - Zerinvary Lajos (zerinvarylajos(AT)yahoo.com), Feb 01 2008 %t A001611 a[0] = 1; a[1] = 2; a[n_] := a[n] = a[n - 2] + a[n - 1] - 1; Table[ a[n], {n, 0, 40} ] %Y A001611 Cf. A000045, A097280, A097281. %Y A001611 Sequence in context: A005856 A157876 A107293 this_sequence A039829 A143588 A032245 %Y A001611 Adjacent sequences: A001608 A001609 A001610 this_sequence A001612 A001613 A001614 %K A001611 nonn,easy %O A001611 0,2 %A A001611 N. J. A. Sloane (njas(AT)research.att.com). Search completed in 0.001 seconds