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A007781 (n+1)^(n+1) - n^n. +0
10
1, 3, 23, 229, 2869, 43531, 776887, 15953673, 370643273, 9612579511, 275311670611, 8630788777645, 293959006143997, 10809131718965763, 426781883555301359, 18008850183328692241, 808793517812627212561 (list; graph; listen)
OFFSET

0,2

COMMENT

a(n)=A000312(n)-A000312(n-1).

(12n^2 + 6n + 1)^2 divides a(6n+1), where (12n^2 + 6n + 1) = (2n+1)^3 - (2n)^3{19,61,127,217,331,469,631,817,1027,1261,...} = A127854(n) = A003215(2n) are the hex (or centered hexagonal) numbers. The prime numbers of the form (12n^2 + 6n + 1) belong to A002407 Cuban primes: primes of the form p = (x^3 - y^3 )/(x - y), x=y+1 (prime hex numbers). - Alexander Adamchuk (alex(AT)kolmogorov.com), Apr 09 2007

REFERENCES

R. P. Stanley, Enumerative Combinatorics, Cambridge, Vol. 2, 1999; see equation (6.7).

LINKS

R. K. Hoeflin, Mega Test

Eric Weisstein's World of Mathematics, Power Difference Prime

FORMULA

|disc(x^(n+1)-x+1)|.

EXAMPLE

a(14) = 10809131718965763 = 3 * 61^2 * 968299894201.

MATHEMATICA

a[n_]:=(n+1)^(n+1)-n^n; [From Vladimir Orlovsky (4vladimir(AT)gmail.com), Dec 11 2008]

CROSSREFS

Cf. A068954, A068955, A068956, A068957, A068146.

Cf. A127854 = Largest number k such that k^2 divides A007781(6n+1). Cf. A003215, A002407.

Sequence in context: A068954 A068955 A151393 this_sequence A068146 A162591 A122009

Adjacent sequences: A007778 A007779 A007780 this_sequence A007782 A007783 A007784

KEYWORD

nonn

AUTHOR

peter.mccormack(AT)its.csiro.au

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Last modified November 27 14:50 EST 2009. Contains 167570 sequences.


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