Search: id:A008316 Results 1-1 of 1 results found. %I A008316 %S A008316 1,1,1,3,3,5,3,30,35,15,70,63,5,105,315,231,35,315,693,429,35,1260,6930, %T A008316 12012,6435,315,4620,18018,25740,12155,63,3465,30030,90090,109395,46189, 693, %U A008316 15015,90090,218790,230945,88179,231,18018,225225,1021020,2078505,1939938, 676039 %V A008316 1,1,-1,3,-3,5,3,-30,35,15,-70,63,-5,105,-315,231,-35,315,-693,429,35, -1260,6930, %W A008316 -12012,6435,315,-4620,18018,-25740,12155,-63,3465,-30030,90090,-109395, 46189,-693, %X A008316 15015,-90090,218790,-230945,88179,231,-18018,225225,-1021020,2078505, -1939938,676039 %N A008316 Triangle of coefficients of Legendre polynomials P_n (x). %D A008316 M. Abramowitz and I. A. Stegun, eds., Handbook of Mathematical Functions, National Bureau of Standards Applied Math. Series 55, 1964 (and various reprintings), p. 798. %H A008316 T. D. Noe, Rows n=0..100 of triangle, flattened %H A008316 M. Abramowitz and I. A. Stegun, eds., Handbook of Mathematical Functions, National Bureau of Standards, Applied Math. Series 55, Tenth Printing, 1972 [alternative scanned copy]. %H A008316 Eric Weisstein's World of Mathematics, Legendre Polynomial %e A008316 1; 1; -1,3; -3,5; 3,-30,35; 15,-70,63; ... %e A008316 P_6(x) = (-5+105x^2-315x^4+231x^6)/16 so T(6,)=-5,105,-315,231. %e A008316 P_5(x) = (15x-70x^3+63x^5)/8 so T(5,)=15,-70,63. %t A008316 Flatten[Table[(LegendreP[i, x]/.{Plus->List, x->1})Max[ Denominator[LegendreP[i, x]/.{Plus->List, x->1}]], {i, 0, 12}]] %o A008316 (PARI) T(n,k)=if(n<0,0,polcoeff(pollegendre(n)*2^valuation((n\2*2)!,2), n%2+2*k)) %Y A008316 Cf. A001790, A001800, A001801. %Y A008316 With zeros: A100258. %Y A008316 Sequence in context: A071053 A094439 A122037 this_sequence A072820 A131950 A116192 %Y A008316 Adjacent sequences: A008313 A008314 A008315 this_sequence A008317 A008318 A008319 %K A008316 sign,tabf,easy,nice %O A008316 0,4 %A A008316 N. J. A. Sloane (njas(AT)research.att.com). %E A008316 More terms from Vit Planocka (planocka(AT)mistral.cz), Sep 28 2002 Search completed in 0.001 seconds