Search: id:A010692 Results 1-1 of 1 results found. %I A010692 %S A010692 10,10,10,10,10,10,10,10,10,10,10,10,10,10,10,10,10,10,10,10,10,10, %T A010692 10,10,10,10,10,10,10,10,10,10,10,10,10,10,10,10,10,10,10,10,10,10, %U A010692 10,10,10,10,10,10,10,10,10,10,10,10,10,10,10,10,10,10,10,10,10,10 %N A010692 Constant sequence. %C A010692 Also the representation of 2 in base 2 followed by 3 written in base 3, 4 in base 4, etc. %C A010692 If A=[A158127] 100*n.^2+2*n (n>0, 102, 404, 906,.,. ,.,); Y=[A010692] 10 (10, 10, 10,.,); X=[A158128] 100*n+1 (n>0, 101, 201, 301, ,. ., ), we have, for all terms, Pell's equation X^2-A*Y^2=1. Example: 101^2-102*10^2=1; 201^2-404*10^2=1; 301^2-906*10^2=1. [From Vincenzo Librandi (vincenzo.librandi(AT)tin.it), Mar 13 2009] %C A010692 If A=[A158129] 100*n.^2-2*n (n>0, 98, 396, 894,.,. ,.,); Y=[A010692] 10 (10, 10, 10,.,); X=[A044812] 100*n-1 (n>0, 99, 199, 299, ,. ., ), we have, for all terms, Pell's equation X^2-A*Y^2=1. Example: 99^2-98*10^2=1; 199^2-396*10^2=1; 299^2-894*10^2=1. [From Vincenzo Librandi (vincenzo.librandi(AT)tin.it), Mar 13 2009] %H A010692 Index entries for sequences related to linear recurrences with constant coefficients %H A010692 Tanya Khovanova, Recursive Sequences %Y A010692 Cf. A158127, A158128 [From Vincenzo Librandi (vincenzo.librandi(AT)tin.it), Mar 13 2009] %Y A010692 Cf. A158129, A044812 [From Vincenzo Librandi (vincenzo.librandi(AT)tin.it), Mar 13 2009] %Y A010692 Sequence in context: A131722 A072803 A163139 this_sequence A109751 A160941 A070565 %Y A010692 Adjacent sequences: A010689 A010690 A010691 this_sequence A010693 A010694 A010695 %K A010692 nonn %O A010692 0,1 %A A010692 N. J. A. Sloane (njas(AT)research.att.com). Search completed in 0.001 seconds