Search: id:A011945
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%I A011945
%S A011945 0,6,84,1170,16296,226974,3161340,44031786,613283664,8541939510,
%T A011945 118973869476,1657092233154,23080317394680,321467351292366,
%U A011945 4477462600698444,62363009058485850
%N A011945 Area of triangles with integral side lengths m-1, m, m+1 and integral 
               area.
%C A011945 Corresponding m's are in A016064. Corresponding values of lesser side 
               give A016064.
%D A011945 E. K. Lloyd "The standard deviation of 1, 2, .., n, Pell's equation and 
               rational triangles", preprint.
%H A011945 Tanya Khovanova, <a href="http://www.tanyakhovanova.com/RecursiveSequences/
               RecursiveSequences.html">Recursive Sequences</a>
%H A011945 P. Yiu, <a href="http://www.math.fau.edu/yiu/RecreationalMathematics2003.pdf">
               "Heron triangles with consecutive sides" in 'Recreational Mathematics' 
               Chap.9.3 pp. 80/360</a>
%H A011945 <a href="Sindx_Rea.html#recLCC">Index entries for sequences related to 
               linear recurrences with constant coefficients</a>
%F A011945 s(n)=[(a+1)/4]*sqrt[3(3+a)(a-1)], where a=A016064(n). - Zak Seidov (zakseidov(AT)yahoo.com), 
               Feb 23 2005
%F A011945 a(n) = 14*a(n-1)-a(n-2); a(1) = 0, a(2) = 6.
%F A011945 G.f.: 6*x^2/(1-14*x+x^2). [From Philippe DELEHAM (kolotoko(AT)wanadoo.fr), 
               Nov 17 2008]
%Y A011945 Equals 6 * A007655(n+1).
%Y A011945 Cf. A003500, A102341, A103974, A103975, A016064.
%Y A011945 Sequence in context: A119576 A098982 A144514 this_sequence A113888 A163947 
               A128575
%Y A011945 Adjacent sequences: A011942 A011943 A011944 this_sequence A011946 A011947 
               A011948
%K A011945 nonn,easy
%O A011945 1,2
%A A011945 E. K. Lloyd
%E A011945 Entry revised by N. J. A. Sloane (njas(AT)research.att.com), Feb 03 2007

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