Search: id:A014105 Results 1-1 of 1 results found. %I A014105 %S A014105 0,3,10,21,36,55,78,105,136,171,210,253,300,351,406,465,528,595,666, %T A014105 741,820,903,990,1081,1176,1275,1378,1485,1596,1711,1830,1953,2080, %U A014105 2211,2346,2485,2628,2775,2926,3081,3240,3403,3570,3741,3916,4095,4278 %N A014105 Second hexagonal numbers: n(2n+1). %C A014105 Note that when starting from {a(n)}^2, equality holds between series of first n+1 and next n consecutive squares : a(n)^2+(a(n)+1)^2+...+(a(n)+n)^2 = (a(n)+n+1)^2+(a(n)+n+2)^2+...(a(n)+2n)^2, e.g. 10^2+11^2+12^2 = 13^2+14^2 - Henry Bottomley (se16(AT)btinternet.com), Jan 22 2001 %C A014105 a(n) = sum of second set of n consecutive even numbers - sum of the first set of n consecutive odd numbers: a(1) = 4-1, a(3) = (8+10+12) - (1+3+5) = 21. - Amarnath Murthy, Nov 07 2002 %C A014105 a(n) = A084849(n) - 1; A100035(a(n)+1) = 1. - Reinhard Zumkeller (reinhard.zumkeller(AT)gmail.com), Oct 31 2004 %C A014105 Also a(n)=3*Sum(tan^2(k*pi/(2(n+1))), k, 1, n); - Ignacio Larrosa (ignacio.larrosa(AT)eresmas.net), Apr 17 2001 %C A014105 If Y is a fixed 3-subset of a (2n+1)-set X then a(n) is the number of (2n-1)-subsets of X intersecting Y. - Milan R. Janjic (agnus(AT)blic.net), Oct 28 2007 %C A014105 a(2*n) = A033585(n); a(3*n) = A144314(n). [From Reinhard Zumkeller (reinhard.zumkeller(AT)gmail.com), Sep 17 2008] %H A014105 Index entries for two-way infinite sequences %H A014105 Index entries for sequences related to linear recurrences with constant coefficients %H A014105 Milan Janjic, Two Enumerative Functions %F A014105 a(n)^2 = n*(a(n)+1 + a(n)+2 + ... + a(n)+2n), e.g. 10^2 = 2*(11 + 12 + 13 +14) - Charlie Marion (charliem(AT)bestweb.net), Jun 15 2003 %F A014105 G.f.: x(3+x)/(1-x)^3. E.g.f.: exp(x)(3x+2x^2). a(n)=A000217(2n)=A000384(-n). %F A014105 Partial sums of odd numbers 3 mod 4, i.e. 3, 3+7, 3+7+11, ... Cf. A001107. - Jon Perry (perry(AT)globalnet.co.uk), Dec 18 2004 %F A014105 a(n) = A126890(n,k) + A126890(n,n-k), 0<=k<=n. - Reinhard Zumkeller (reinhard.zumkeller(AT)gmail.com), Dec 30 2006 %F A014105 a(n)=4*n+a(n-1)-5 (with a(1)=0) [From Vincenzo Librandi (vincenzo.librandi(AT)tin.it), Nov 08 2009] %e A014105 For n=2, a(2)=4*2+0-5=3; n=3, a(3)=4*3+3-5=10; n=4, a(4)=4*4+10-5=21 [From Vincenzo Librandi (vincenzo.librandi(AT)tin.it), Nov 08 2009] %p A014105 seq(binomial(2*n+1,2), n=0..46); - Zerinvary Lajos (zerinvarylajos(AT)yahoo.com), Jan 21 2007 %p A014105 a:=n->sum(j, j=0..n): seq(a(2*n), n=0..46); - Zerinvary Lajos (zerinvarylajos(AT)yahoo.com), Apr 30 2007 %p A014105 with(finance):seq(add(cashflows([n,k,k], 0 ),k=1..n),n=0..51); - Zerinvary Lajos (zerinvarylajos(AT)yahoo.com), Jun 30 2008 %p A014105 a:=n->sum(1+sum(2, k=1..n), k=1..n):seq(a(n), n=0...43); [From Zerinvary Lajos (zerinvarylajos(AT)yahoo.com), Aug 24 2008] %t A014105 s=0;lst={s};Do[s+=n++ +3;AppendTo[lst, s], {n, 0, 6!, 4}];lst [From Vladimir Orlovsky (4vladimir(AT)gmail.com), Nov 16 2008] %o A014105 (PARI) a(n)=n*(2*n+1) %Y A014105 Cf. A000217, A000384. %Y A014105 Second column of array A094416. %Y A014105 Cf. A100040, A100041. %Y A014105 A081266, A144312. [From Reinhard Zumkeller (reinhard.zumkeller(AT)gmail.com), Sep 17 2008] %Y A014105 Sequence in context: A073604 A004194 A097590 this_sequence A146012 A027917 A038347 %Y A014105 Adjacent sequences: A014102 A014103 A014104 this_sequence A014106 A014107 A014108 %K A014105 nonn,easy,new %O A014105 0,2 %A A014105 N. J. A. Sloane (njas(AT)research.att.com). Search completed in 0.002 seconds