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Search: id:A014117
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| A014117 |
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Numbers n such that m^(n+1) = m mod n holds for all m. |
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+0 7
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OFFSET
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1,2
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COMMENT
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"Somebody incorrectly remembered Fermat's little theorem as saying that the congruence a^{n+1} = a (mod n) holds for all a if n is prime" (Zagier). The sequence gives the set of integers n for which this property is in fact true.
If i = j (mod n), then m^i = m^j (mod n) for all m. The latter congruence generally holds for any (m, n)=1 with i = j (mod k), k being the order of m modulo n, i.e. the least power k for which m^k = 1 (mod n). - Lekraj Beedassy (blekraj(AT)yahoo.com), Jul 04 2002
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REFERENCES
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J. Dyer-Bennet, "A Theorem in Partitions of the Set of Positive Integers", Amer. Math. Monthly, 47(1940) pp. 152-4.
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LINKS
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D. Zagier, Problems posed at the St Andrews Colloquium, 1996
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CROSSREFS
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Sequence in context: A152479 A115961 A123137 this_sequence A054377 A007018 A100016
Adjacent sequences: A014114 A014115 A014116 this_sequence A014118 A014119 A014120
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KEYWORD
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nonn,fini,full,nice
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AUTHOR
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David Broadhurst (D.Broadhurst(AT)open.ac.uk)
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