0,6
For n>0, a(n) = 2*Fibonacci(n+3) + 2^n + [5(-1)^n - 19]*3^[n/2-1]. - R. Stephan, May 13 2004
Sequence in context: A085286 A062085 A147800 this_sequence A126171 A002839 A109194
Adjacent sequences: A027558 A027559 A027560 this_sequence A027562 A027563 A027564
nonn
R. K. Guy (rkg(AT)cpsc.ucalgary.ca), callan(AT)bayes.stat.wisc.edu (David Callan)
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