Search: id:A030101
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%I A030101
%S A030101 0,1,1,3,1,5,3,7,1,9,5,13,3,11,7,15,1,17,9,25,5,21,13,29,3,19,11,27,7,
               23,
%T A030101 15,31,1,33,17,49,9,41,25,57,5,37,21,53,13,45,29,61,3,35,19,51,11,43,27,
%U A030101 59,7,39,23,55,15,47,31,63,1,65,33,97,17,81,49,113,9,73,41,105,25,89,57
%N A030101 a(n) is the number produced when n is converted to base 2, reversed and 
               then converted back to base 10.
%C A030101 As with decimal reversal initial zeros are ignored, otherwise the reverse 
               of 1 would be 1000000... ad infinitum.
%C A030101 Numerators of the binary van der Corput sequence. - Eric S Rowland (erowland(AT)math.rutgers.edu), 
               Feb 12 2008
%D A030101 Solutions to 17th USA Mat. Olympiad, Math. Mag., 62 (1989), 210-214 (#3).
%H A030101 T. D. Noe, <a href="b030101.txt">Table of n, a(n) for n=0..10000</a>
%H A030101 Michael Gilleland, <a href="selfsimilar.html">Some Self-Similar Integer 
               Sequences</a>
%H A030101 Wikipedia, <a href="http://en.wikipedia.org/wiki/Van_der_Corput_sequence">
               van der Corput sequence</a>.
%F A030101 a(n) = 0, a(2n) = a(n), a(2n+1) = a(n) + 2^([log2(n)]+1). For n>0, a(n) 
               = 2*A030109(n) - 1. - Ralf Stephan (ralf(AT)ark.in-berlin.de), Sep 
               15 2003
%e A030101 a(100) = 19 because 100 (base 10) = 1100100 (base 2) and R(1100100 (base 
               2)) = 10011 (base 2) = 19 (base 10)
%t A030101 Table[FromDigits[Reverse[IntegerDigits[i, 2]], 2], {i, 0, 80}]
%o A030101 (PARI) a(n)=if(n<1,0,subst(Polrev(binary(n)),x,2))
%Y A030101 Cf. A030109, A036044, A056539, A004086.
%Y A030101 Sequence in context: A040026 A106609 A093474 this_sequence A162742 A081432 
               A136655
%Y A030101 Adjacent sequences: A030098 A030099 A030100 this_sequence A030102 A030103 
               A030104
%K A030101 nonn,base,nice
%O A030101 0,4
%A A030101 David W. Wilson (davidwwilson(AT)comcast.net)

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