Search: id:A031150 Results 1-1 of 1 results found. %I A031150 %S A031150 1,2,4,5,6,12,18,43,80,154,191,228,456,684,1633,3038,5848,7253,8658, %T A031150 17316,25974,62011,115364,222070,275423,328776,657552,986328, %U A031150 2354785,4380794,8432812,10458821,12484830,24969660,37454490 %N A031150 Appending a digit to n^2 gives another perfect square. %C A031150 Square root of 'Squares from A023110 with last digit removed'. %e A031150 5^2 = 25 and 16^2 = 256, so 5 is in the sequence. 115364^2 = 13308852496, 364813^2 = 133088524969 %p A031150 for i from 1 to 150000 do if (floor(sqrt(10 * i^2 + 9)) > floor(sqrt(10 * i^2))) then print(i) end if end do; %Y A031150 Cf. A023110, A030686, A030687, A053784. %Y A031150 Sequence in context: A113631 A101951 A006539 this_sequence A125775 A058637 A026473 %Y A031150 Adjacent sequences: A031147 A031148 A031149 this_sequence A031151 A031152 A031153 %K A031150 nonn,base %O A031150 0,2 %A A031150 Patrick De Geest (pdg(AT)worldofnumbers.com) Search completed in 0.001 seconds