|
Search: id:A035610
|
|
|
| A035610 |
|
G.f.: 3/(1+2*sqrt(1-12*x)). |
|
+0 5
|
|
| 1, 4, 28, 232, 2092, 19864, 195352, 1970896, 20275660, 211823800, 2240795848, 23951289520, 258255469816, 2805534253552, 30675477376432, 337306474674592, 3727578443380492, 41376874025687032, 461121792658583272
(list; graph; listen)
|
|
|
OFFSET
|
0,2
|
|
|
COMMENT
|
Number of walks of length 2n on the 4-regular tree beginning and ending at some fixed vertex. The generating function for the corresponding sequence for the m-regular tree is 2*(m-1)/(m-2+m*sqrt(1-4*(m-1)*x)). When m=2 this reduces to the usual generating function for the central binomial coefficients. - Paul Boddington (psb(AT)maths.warwick.ac.uk), Nov 11 2003
Main diagonal of the array A(0,j)=A(i,0)=1 for i,j>=0 and for i,j>=1 A(i,j)=min{A(i,j-1)+3*A(i-1,j); 3*A(i,j-1)+A(i-1,j)} - Benoit Cloitre (benoit7848c(AT)orange.fr), Aug 05 2004
Hankel transform is A133461 . - Philippe DELEHAM (kolotoko(AT)wanadoo.fr), Dec 01 2007
|
|
FORMULA
|
a(n) = Sum{k, 0<=k<=n}A039599(n,k)*3^(n-k). - Philippe DELEHAM (kolotoko(AT)wanadoo.fr), Aug 25 2007
Contribution from Paul Barry (pbarry(AT)wit.ie), Sep 15 2009: (Start)
G.f.: 1/(1-4x*c(3x)), c(x) the g.f. of A000108;
G.f.: 1/(1-4x/(1-3x/(1-3x/(1-3x/(1-3x/(1-.... (continued fraction);
G.f.: 1/(1-4x-12x^2/(1-6x-9x^2/(1-6x-9x^2/(1-6x-9x^2/(1-... (continued fraction).
Integral representation: a(n)=(2/pi)*Int(x^n*sqrt(x(12-x))/(16-x),x,0,12). (End)
|
|
EXAMPLE
|
a(2)=28 because there are 4*4=16 walks whose second step is to return to the starting vertex and 4*3=12 walks whose second step is to move away from the starting vertex.
|
|
MATHEMATICA
|
CoefficientList[ Series[3/(1 + 2Sqrt[1 - 12x]), {x, 0, 19}], x] (from Robert G. Wilson v Nov 12 2003)
|
|
CROSSREFS
|
Cf. A089022.
Sequence in context: A121203 A152599 A089023 this_sequence A046904 A030444 A093877
Adjacent sequences: A035607 A035608 A035609 this_sequence A035611 A035612 A035613
|
|
KEYWORD
|
nonn
|
|
AUTHOR
|
N. J. A. Sloane (njas(AT)research.att.com).
|
|
|
Search completed in 0.002 seconds
|