Search: id:A049998 Results 1-1 of 1 results found. %I A049998 %S A049998 1,1,1,1,1,1,2,1,1,3,2,1,5,3,1,1,8,5,1,2,13,8,1,1,3,21,13,2,1,5,34,21, 3, %T A049998 1,1,8,55,34,5,1,2,13,89,55,8,1,1,3,21,144,89,13,2,1,5,34,233,144,21,3, %U A049998 1,1,8,55,377,233,34,5,1,2,13,89,610,377,55,8,1,1,3,21,144,987,610,89 %N A049998 a(n)=b(n)-b(n-1), where b=A049997 (differences of products of Fibonacci numbers). %C A049998 David W. Wilson conjectured (Dec 14 2005) that this sequence consists only of Fibonacci numbers. Proofs were found by Franklin T. Adams-Watters and Don Reble, Dec 14 2005. The following is Reble's proof: %C A049998 Rearrange A049997, as suggested by Bernardo Boncompagni (redgolpe(AT)redgolpe.com): %C A049998 1 %C A049998 2 %C A049998 3 4 %C A049998 5 6 %C A049998 8 9 10 %C A049998 13 15 16 %C A049998 21 24 25 26 %C A049998 34 39 40 42 %C A049998 55 63 64 65 68 %C A049998 89 102 104 105 110 %C A049998 144 165 168 169 170 178 %C A049998 233 267 272 273 275 288 %C A049998 377 432 440 441 442 445 466 %C A049998 Then we know that %C A049998 F(a+1) * F(a-1) - F(a) * F(a) = (-1)^a %C A049998 F(a+1) * F(b-1) - F(a-1) * F(b+1) %C A049998 = + (-1)^b F(a-b), if a>b %C A049998 = - (-1)^a F(b-a), if a