Search: id:A053833 Results 1-1 of 1 results found. %I A053833 %S A053833 0,1,2,3,4,5,6,7,8,9,10,11,12,1,2,3,4,5,6,7,8,9,10,11,12,13,2,3,4,5,6, %T A053833 7,8,9,10,11,12,13,14,3,4,5,6,7,8,9,10,11,12,13,14,15,4,5,6,7,8,9,10, %U A053833 11,12,13,14,15,16,5,6,7,8,9,10,11,12,13,14,15,16,17,6,7,8,9,10,11,12 %N A053833 Sum of digits of n written in base 13. %C A053833 a(n) = A138530(n,13) for n > 12. - Reinhard Zumkeller (reinhard.zumkeller(AT)gmail.com), Mar 26 2008 %H A053833 Eric Weisstein's World of Mathematics, Digit Sum %F A053833 a(0)=0, a(13n+i)=a(n)+i 0<=i<=12; a(n)=n-12*(sum(k>0, floor(n/13^k)). - Benoit Cloitre, Dec 19, 2002 %e A053833 a(20)=1+7=8 because 20 is written as 17 base 13 %o A053833 (PARI) a(n)=if(n<1,0,if(n%13,a(n-1)+1,a(n/13))) %Y A053833 Cf. A000120, A007953. %Y A053833 Sequence in context: A121759 A072778 A034326 this_sequence A087999 A106614 A043272 %Y A053833 Adjacent sequences: A053830 A053831 A053832 this_sequence A053834 A053835 A053836 %K A053833 base,nonn %O A053833 0,3 %A A053833 Henry Bottomley (se16(AT)btinternet.com), Mar 28 2000 Search completed in 0.001 seconds