Search: id:A054849 Results 1-1 of 1 results found. %I A054849 %S A054849 1,12,84,448,2016,8064,29568,101376,329472,1025024,3075072,8945664, %T A054849 25346048,70189056,190513152,508035072,1333592064,3451650048, %U A054849 8820883456,22284337152,55710842880,137950658560,338606161920 %N A054849 2^(n-5)*C(n,5). Number of 5D hypercubes in an n-dimensional hypercube. %C A054849 With 5 leading zeros, binomial transform of C(n,5) - Paul Barry (pbarry(AT)wit.ie), Apr 10 2003 %C A054849 If X_1,X_2,...,X_n is a partition of a 2n-set X into 2-blocks then, for n>4, a(n) is equal to the number of (n+5)-subsets of X intersecting each X_i (i=1,2,...,n). - Milan R. Janjic (agnus(AT)blic.net), Jul 21 2007 %C A054849 With a different offset, number of n-permutations (n=6) of 3 objects: u,v,z with repetition allowed, containing exactly five (5) u's. Example: a(1)=12 because we have uuuuuv, uuuuvu, uuuvuu, uuvuuu, uvuuuu, vuuuuu, uuuuuz, uuuuzu, uuuzuu, uuzuuu, uzuuuu and zuuuuu. - Zerinvary Lajos (zerinvarylajos(AT)yahoo.com), Jun 13 2008 %H A054849 Milan Janjic, Two Enumerative Functions %F A054849 a(n)=2*a(n-1)+A003472(n-1) %F A054849 G.f. 1/(1-2x)^6 E.g.f. exp(2x)(x^5/5!) (with 5 leading zeros) - Paul Barry (pbarry(AT)wit.ie), Apr 10 2003 %p A054849 seq(binomial(n+5,5)*2^n,n=0..22); - Zerinvary Lajos (zerinvarylajos(AT)yahoo.com), Jun 13 2008 %o A054849 (Other) SAGE: [lucas_number2(n, 2, 0)*binomial(n,5)/32 for n in xrange(5, 28)] [From Zerinvary Lajos (zerinvarylajos(AT)yahoo.com), Mar 10 2009] %Y A054849 Cf. A000079, A001787, A001788, A001789, A003472, A002409, A054851, A038207. %Y A054849 Equals 2 * A082139. First differences are in A006975. %Y A054849 Sequence in context: A085409 A111464 A004407 this_sequence A000761 A003209 A155645 %Y A054849 Adjacent sequences: A054846 A054847 A054848 this_sequence A054850 A054851 A054852 %K A054849 easy,nonn %O A054849 5,2 %A A054849 Henry Bottomley (se16(AT)btinternet.com), Apr 14 2000 %E A054849 More terms from James A. Sellers (sellersj(AT)math.psu.edu), Apr 15 2000 Search completed in 0.002 seconds