|
Search: id:A055775
|
|
| |
|
| 1, 1, 2, 4, 10, 26, 64, 163, 416, 1067, 2755, 7147, 18613, 48638, 127463, 334864, 881657, 2325750, 6145596, 16263866, 43099804, 114356611, 303761260, 807692034, 2149632061, 5726042115, 15264691107, 40722913454, 108713644516
(list; graph; listen)
|
|
|
OFFSET
|
0,3
|
|
|
COMMENT
|
Stirling's approximation for n! suggests that this should be about e^n/sqrt(pi*2n). R. W. Gosper has noted that e^n/sqrt(pi*(2n+1/3)) is significantly better.
n^n/n! = A001142(n)/A001142(n-1), where A001142(n) is product{k=0 to n} C(n,k) (where C() is a binomial coefficient). - Leroy Quet, May 01 2004
|
|
LINKS
|
Leroy Quet, Home Page (listed in lieu of email address)
Eric Weisstein's World of Mathematics, Stirling's Approximation for n!
|
|
FORMULA
|
a(n) =[A000312(n)/A000142(n)]
|
|
EXAMPLE
|
a(5)=26 since 5^5=3125, 5!=120, 3125/120=26.0416666...
|
|
MATHEMATICA
|
lst={}; Do[AppendTo[lst, Floor[n^n/n! ]], {n, 5!}]; lst [From Vladimir Orlovsky (4vladimir(AT)gmail.com), Jan 15 2009]
|
|
CROSSREFS
|
Cf. A073225, A094082.
Cf. A053042, A036679, A061711 [From Vladimir Orlovsky (4vladimir(AT)gmail.com), Jan 15 2009]
Sequence in context: A100605 A154322 A090031 this_sequence A090032 A090377 A151278
Adjacent sequences: A055772 A055773 A055774 this_sequence A055776 A055777 A055778
|
|
KEYWORD
|
nonn
|
|
AUTHOR
|
Henry Bottomley (se16(AT)btinternet.com), Jul 12 2000
|
|
EXTENSIONS
|
More terms from James A. Sellers (sellersj(AT)math.psu.edu), Jul 13 2000
|
|
|
Search completed in 0.002 seconds
|
