0,2

a(n)=A000096 + 7 * A001477, a(n)=A056121 + A001477 and a(n)=A051942 - A001477 - Zerinvary Lajos (zerinvarylajos(AT)yahoo.com), Oct 01 2006

a(n) = A126890(n,8) for n>7. - Reinhard Zumkeller (reinhard.zumkeller(AT)gmail.com), Dec 30 2006

G.f.(x)=x(9-8x)/(1-x)^3.

a(n)=C(n,2)-8*n,n>=17 - Zerinvary Lajos (zerinvarylajos(AT)yahoo.com), Nov 26 2006

If we define f(n,i,a)=sum(binomial(n,k)*stirling1(n-k,i)*product(-a-j,j=0..k-1),k=0..n-i), then a(n) = -f(n,n-1,9), for n>=1. [From Milan R. Janjic (agnus(AT)blic.net), Dec 20 2008]

a(n)=n+a(n-1)+7 (with a(1)=0) [From Vincenzo Librandi (vincenzo.librandi(AT)tin.it), Nov 19 2009]

For n=2, a(2)=2+0+7=9; n=3, a(3)=3+9+7=19; n=4, a(4)=4+19+7=30 [From Vincenzo Librandi (vincenzo.librandi(AT)tin.it), Nov 19 2009]

a:=n->sum(floor(k+2*n/(k+n)), k=8..n): seq(a(n), n=7..57); - Zerinvary Lajos (zerinvarylajos(AT)yahoo.com), Oct 01 2006

[seq(binomial(n, 2)-8*n, n=17..67)]; - Zerinvary Lajos (zerinvarylajos(AT)yahoo.com), Nov 26 2006

a:=n->sum(n, j=18..n): seq(a(n)/2, n=17..67); - Zerinvary Lajos (zerinvarylajos(AT)yahoo.com), Feb 17 2008

a:=n->sum(denom (k/(k+3)), k=6..n): seq(a(n), n=5..55); - Zerinvary Lajos (zerinvarylajos(AT)yahoo.com), May 31 2008

with(finance):seq(add(cashflows([2, k, 6], 0 ), k=1..n), n=0..50); - Zerinvary Lajos (zerinvarylajos(AT)yahoo.com), Jun 22 2008

i=-8; s=0; lst={}; Do[s+=n+i; If[s>=0, AppendTo[lst, s]], {n, 0, 6!, 1}]; lst [From Vladimir Orlovsky (4vladimir(AT)gmail.com), Oct 29 2008]

Cf. A056121.

Cf. A000096, A056121, A051942, A056000, A001477.

Cf. A001477, A098849, A120071, A132760, A132761, A132765.

Sequence in context: A043525 A031499 A017377 this_sequence A051811 A034056 A157034

Adjacent sequences: A056123 A056124 A056125 this_sequence A056127 A056128 A056129

easy,nonn,new

Barry E. Williams, Jul 07 2000

More terms from James A. Sellers (sellersj(AT)math.psu.edu), Jul 10 2000