Search: id:A057105
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%I A057105
%S A057105 1,2,7,7,4,17,14,1,14,31,23,8,9,28,49,34,17,2,23,46,71,47,28,7,16,41,68,
               97,
%T A057105 62,41,18,7,34,63,94,127,79,56,31,4,25,56,89,124,161,98,73,46,17,14,47,
               82,
%U A057105 119,158,199,119,92,63,32,1,36,73,112,153,196,241,142,113,82,49,14,23,
               62,103
%V A057105 1,-2,7,-7,4,17,-14,-1,14,31,-23,-8,9,28,49,-34,-17,2,23,46,71,-47,-28,
               -7,16,41,68,97,
%W A057105 -62,-41,-18,7,34,63,94,127,-79,-56,-31,-4,25,56,89,124,161,-98,-73,-46,
               -17,14,47,82,
%X A057105 119,158,199,-119,-92,-63,-32,1,36,73,112,153,196,241,-142,-113,-82,-49,
               -14,23,62,103
%N A057105 Triangle of numbers (when unsigned) related to congruum problem: T(n,
               k)=k^2+2nk-n^2 with n>k>0 and starting at T(2,1)=1.
%C A057105 Signed values are only relevant for the explicit formula.
%H A057105 Eric Weisstein's World of Mathematics, <a href="http://mathworld.wolfram.com/
               CongruumProblem.html">Link to a section of The World of Mathematics.</
               a>
%F A057105 Unsigned: a(n) =sqrt(A055096(n)^2-A057103(n)) =sqrt(A056203(n)^2-2*A057103(n)).
%e A057105 a(1)=T(2,1)=1^2+2*2*1-2^2=1
%Y A057105 Cf. A057102. The congruum problem is about finding solutions for h (A057103) 
               where there are integers x (A055096), y (A057105 unsigned) and z 
               (A056203) such that h=x^2-y^2=z^2-x^2.
%Y A057105 Sequence in context: A020770 A164767 A021977 this_sequence A016536 A063503 
               A068386
%Y A057105 Adjacent sequences: A057102 A057103 A057104 this_sequence A057106 A057107 
               A057108
%K A057105 sign,tabl
%O A057105 1,2
%A A057105 Henry Bottomley (se16(AT)btinternet.com), Aug 02 2000

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