Search: id:A059558 Results 1-1 of 1 results found. %I A059558 %S A059558 4,8,12,16,20,24,28,32,36,40,44,48,52,56,60,64,68,72,76,80,84,88,92, %T A059558 96,100,104,108,112,116,120,124,128,132,136,140,144,148,152,156,160, %U A059558 164,168,172,176,180,184,188,192,196,200,204,208,212,216,220,224,228 %N A059558 Beatty sequence for 1+1/gamma^2. %C A059558 Also, each entry with two appended 0's corresponds to a terminating-century leap year. - Lekraj Beedassy (blekraj(AT)yahoo.com), Aug 28 2006 %C A059558 The first term where this sequence breaks the progression a(n) = a(n-1) + 4 is a(715) = 2861. - Max Alekseyev, Mar 03 2007 %D A059558 Fraenkel, Aviezri S.; Levitt, Jonathan; and Shimshoni, Michael; Characterization of the set of values f(n)=[n alpha], n=1,2,... Discrete Math.2 (1972), no.4,335-345. %H A059558 Harry J. Smith, Table of n, a(n) for n=1,...,2000 %H A059558 Tanya Khovanova, Non Recursions %H A059558 Eric Weisstein's World of Mathematics, Link to a section of The World of Mathematics. %H A059558 Index entries for sequences related to Beatty sequences %F A059558 a(n)=8*n-a(n-1)-4 (with a(1)=4) [From Vincenzo Librandi (vincenzo.librandi(AT)tin.it), Nov 24 2009] %e A059558 For n02, a(2)=8*2-4-4=8; n=3, a(3)=8*3-8-4=12; n=4, a(4)=8*4-12-4=16 [From Vincenzo Librandi (vincenzo.librandi(AT)tin.it), Nov 24 2009] %o A059558 (PARI) { default(realprecision, 100); b=1 + 1/Euler^2; for (n = 1, 2000, write("b059558.txt", n, " ", floor(n*b)); ) } [From Harry J. Smith (hjsmithh(AT)sbcglobal.net), Jun 28 2009] %Y A059558 Beatty complement is A059557. %Y A059558 Sequence in context: A076310 A161352 A008586 this_sequence A008574 A085127 A059532 %Y A059558 Adjacent sequences: A059555 A059556 A059557 this_sequence A059559 A059560 A059561 %K A059558 nonn,easy,new %O A059558 1,1 %A A059558 Mitch Harris (Harris.Mitchell(AT)mgh.harvard.edu), Jan 22, 2001 Search completed in 0.001 seconds