Search: id:A059929 Results 1-1 of 1 results found. %I A059929 %S A059929 0,2,3,10,24,65,168,442,1155,3026,7920,20737,54288,142130,372099, %T A059929 974170,2550408,6677057,17480760,45765226,119814915,313679522, %U A059929 821223648,2149991425,5628750624,14736260450,38580030723 %N A059929 Fib(n)*Fib(n+2). %C A059929 Expansion of golden ratio (1+sqrt(5))/2 as an infinite product: phi = prod(i=0, infty, (1+1/(fibonacci(2i+1) * fibonacci(2i+3)-1)) * (1-1/ (fibonacci(2i+2) * fibonacci(2i+4)+1))) - Thomas Baruchel (baruchel(AT)users.sourceforge.net), Nov 11 2003 %H A059929 Harry J. Smith, Table of n, a(n) for n=0,...,500 %H A059929 M. Renault, Dissertation %H A059929 M. Waldschmidt, Open Diophantine problems %H A059929 E. H. Kuo, Applications of graphical condensation for enumerating matchings and tilings %F A059929 a(n) = Fib(n+1)^2-(-1)^n = A007598(n+1)+A033999(n+1) = A000045(n+1)^2-A033999(n) %F A059929 G.f.: [2x-x^2]/[(1+x)(1-3x+x^2)]. %F A059929 Sum[n=1..inf, 1/a(n)] = 1, Sum[n=1..inf, (-1)^n/a(n)] = 2-sqrt(5). %F A059929 Sum[n=1..inf, 1/a(2n-1)] = 1/phi = (sqrt(5)-1)/2. - Franz Vrabec (franz.vrabec(AT)aon.at), Sep 15 2005 %F A059929 1 = 1/2 + 1/3 + 1/10 + 1/24 + 1/65 + 1/168 + ..., = 1/(1*2) + 1/(1*3) + 1/(2*5) + 1/(3*8) + ... - Gary W. Adamson (qntmpkt(AT)yahoo.com), Mar 16 2008 %F A059929 Sum[n=1..inf, 1/a(2n)] = (3-sqrt(5))/2. [From Franz Vrabec (franz.vrabec(AT)aon.at), Nov 30 2009] %p A059929 with (combinat):a:=n->fibonacci(n)*fibonacci(n+2): seq(a(n), n=0..26); - Zerinvary Lajos (zerinvarylajos(AT)yahoo.com), Oct 07 2007 %t A059929 Table[Fibonacci[n]*Fibonacci[n+2],{n,0,60}] [From Vladimir Orlovsky (4vladimir(AT)gmail.com), Nov 17 2009] %o A059929 (PARI) { for (n=0, 500, write("b059929.txt", n, " ", fibonacci(n)*fibonacci(n + 2)); ) } [From Harry J. Smith (hjsmithh(AT)sbcglobal.net), Jun 30 2009] %Y A059929 Bisection of A070550. %Y A059929 First differences of A059840. %Y A059929 Sequence in context: A130002 A162034 A105286 this_sequence A123029 A103018 A005158 %Y A059929 Adjacent sequences: A059926 A059927 A059928 this_sequence A059930 A059931 A059932 %K A059929 nonn,new %O A059929 0,2 %A A059929 Henry Bottomley (se16(AT)btinternet.com), Feb 09 2001 Search completed in 0.001 seconds