Search: id:A060058 Results 1-1 of 1 results found. %I A060058 %S A060058 1,1,1,1,5,5,1,14,61,61,1,30,331,1385,1385,1,55,1211,12284,50521,50521, %T A060058 1,91,3486,68060,663061,2702765,2702765,1,140,8526,281210,5162421, %U A060058 49164554,199360981,199360981,1,204 %N A060058 Triangle of numbers related to A000330 (sum of squares) and A000364 (Euler numbers). %C A060058 Row sums give A060059. Columns give A000012 (powers of 1), A000330 (sum of squares), A060060-2 for m=0,...,4. Main diagonal gives Euler numbers A000364. See triangle A060074. %H A060058 W. Lang, First 9 rows. %F A060058 a(n, m) = a(n-1, m)+((n+1-m)^2)*a(n, m-1), a(n, -1) := 0, a(0, 0)=1, a(n, m)=0 if n= m >= 0, with the rectangular array ay(n, m) := sum((j^2)*ay(j+1, m-1), j=1..n), n >= 0, m >= 1; input: ay(n, 0)=1 (iterated sums of squares). %F A060058 G.f. for m-th column: 1/(1-x) for m=0, (x^m)*sum(A060063(m, k)*x^k, k=0..m)/ (1-x)^(3*m+1), m >= 1. %F A060058 Recursion for g.f.s for m-th column: (1-x)*G(m, x)= x*G''(m-1, x)- G'(m-1, x) + G(m-1, x)/x, m>=2; G(1, x)=x*(1+x)/(1-x)^4; the apostrophe denotes differentiation w.r.t. x. G(0, x)=1/(1-x). (W. Lang, added Feb 13 2004.) %e A060058 {1}; {1,1}; {1,5,5,}; {1,14,61,61}; ... %Y A060058 Sequence in context: A154945 A011094 A075298 this_sequence A092766 A060074 A011501 %Y A060058 Adjacent sequences: A060055 A060056 A060057 this_sequence A060059 A060060 A060061 %K A060058 nonn,easy,tabl %O A060058 0,5 %A A060058 Wolfdieter Lang (wolfdieter.lang(AT)physik.uni-karlsruhe.de), Mar 16 2001 Search completed in 0.001 seconds