Search: id:A060851
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%I A060851
%S A060851 3,81,1215,15309,177147,1948617,20726199,215233605,2195382771,
%T A060851 22082967873,219667417263,2165293113021,21182215236075,205891132094649,
%U A060851 1990280943581607,19147875284802357,183448998696332259
%N A060851 (2n-1) * (3^(2n-1)).
%D A060851 S. R. Finch, Mathematical Constants, Cambridge, 2003, pp. 28-40.
%H A060851 Harry J. Smith, <a href="b060851.txt">Table of n, a(n) for n=1,...,200</
               a>
%H A060851 S. R. Finch, <a href="http://algo.inria.fr/bsolve/constant/euler/euler.html">
               Euler' s constant C0</a>
%H A060851 Xavier Gourdon and Pascal Sebah, <a href="http://numbers.computation.free.fr/
               Constants/Miscellaneous/zeta.html">Riemann's zeta function</a>
%H A060851 Simon Plouffe, <a href="http://pi.lacim.uqam.ca/eng/records_en.html#others">
               Other interesting computations</a>
%e A060851 ln(2) = sum( 2 / a(n)) for n = 1..infinity
%e A060851 C0 = sum( 2 / a(n) - zeta(2n+1) / [ ( 2^(2n)) * (2n+1) ] )
%e A060851 C0 = sum( [ (4n+2) / a(n) - zeta(2n+1) / (2^(2n)) ] / (2n+1))
%e A060851 7/4= sum( [ (4n+2) / a(n) - zeta(2n+1) / (2^(2n)) ] )
%e A060851 7/8= sum( [ (2n+1) / a(n) - zeta(2n+1) / (2^(2n+1)) ] )
%o A060851 (PARI) { for (n=1, 200, write("b060851.txt", n, " ", (2*n - 1)*(3^(2*n 
               - 1))); ) } [From Harry J. Smith (hjsmithh(AT)sbcglobal.net), Jul 
               13 2009]
%Y A060851 For ln(2) see A002162, for Euler's constant C0 see A001620.
%Y A060851 Sequence in context: A116009 A068562 A123656 this_sequence A116179 A013732 
               A060722
%Y A060851 Adjacent sequences: A060848 A060849 A060850 this_sequence A060852 A060853 
               A060854
%K A060851 nonn,easy
%O A060851 1,1
%A A060851 Frank Ellermann (Frank.Ellermann(AT)t-online.de), May 03 2001
%E A060851 More terms from Larry Reeves (larryr(AT)acm.org), May 07 2001

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