Search: id:A061603 Results 1-1 of 1 results found. %I A061603 %S A061603 1,1,1,1,1,1,1,1,1,1,3628800,39916800,239500800,1037836800,3632428800, %T A061603 10897286400,29059430400,70572902400,158789030400,335221286400, %U A061603 1216451004088320000,25545471085854720000,281000181944401920000 %N A061603 n! / {product of factorials of the digits of n}. %C A061603 It can be shown that the terms obtained by the above formula are positive integers using the fact that k! divides a product of k consecutive numbers. %H A061603 Harry J. Smith, Table of n, a(n) for n=0,...,100 %e A061603 a(12) = (12!) / { (1!)(2!) = 239500800. %o A061603 (PARI) { for (n=0, 100, p=1; x=n; until (x==0, p*=(x - 10*(x\10))!; x\=10); write("b061603.txt", n, " ", n!/p) ) } [From Harry J. Smith (hjsmithh(AT)sbcglobal.net), Jul 25 2009] %Y A061603 Cf. A061602. %Y A061603 Sequence in context: A127229 A068158 A011521 this_sequence A153761 A133132 A071552 %Y A061603 Adjacent sequences: A061600 A061601 A061602 this_sequence A061604 A061605 A061606 %K A061603 nonn,base,easy %O A061603 0,11 %A A061603 Amarnath Murthy (amarnath_murthy(AT)yahoo.com), May 19 2001 %E A061603 Corrected and extended by Vladeta Jovovic (vladeta(AT)eunet.rs), May 19 2001 Search completed in 0.001 seconds