Search: id:A061816 Results 1-1 of 1 results found. %I A061816 %S A061816 0,1,2,3,4,5,6,7,8,9,1,11,252,494,252,525,272,272,252,171,2,252,22,161, %T A061816 696,525,494,999,252,232,3,434,2112,33,272,525,252,111,494,585,4,656, %U A061816 252,989,44,585,414,141,2112,343,5,969,676,212,27972,55,616,171,232 %N A061816 Obtain m by omitting trailing zeros from n (cf. A004151); a(n) = smallest multiple k*m which is a palindrome. %C A061816 Every positive integer is a factor of a palindrome, unless it is a multiple of 10 (D. G. Radcliffe, see links). %C A061816 Every integer n has a multiple of the form 99...9900...00. To see that n has a multiple that's a palindrome (allowing 0's on the left) with even digits, let 9n divide 99...9900...00; then n divides 22...2200...00. - Dean Hickerson, Jun 29, 2001. %H A061816 P. De Geest, Smallest multipliers to make a number palindromic. %e A061816 For n = 30 we have m = 3, 1*m = 3 is a palindrome, so a(30) = 3. For n = m = 12 the smallest palindromic multiple is 21*m = 252, so a(12) = 252. %o A061816 (ARIBAS): stop := 200000; for n := 0 to maxarg do k := 1; test := true; while test and k < stop do mp := omit_trailzeros(n)*k; if test := mp <> int_reverse(mp) then inc(k); end; end; if k < stop then write(mp, " "); else write(-1," "); end; end; %Y A061816 Cf. A050782, A062293, A061915, A061916. Values of k are given in A061906. %Y A061816 Sequence in context: A084011 A004086 A121760 this_sequence A083960 A138795 A093017 %Y A061816 Adjacent sequences: A061813 A061814 A061815 this_sequence A061817 A061818 A061819 %K A061816 base,easy,nonn %O A061816 0,3 %A A061816 Klaus Brockhaus (klaus-brockhaus(AT)t-online.de), Jun 25 2001 Search completed in 0.001 seconds