Search: id:A061906 Results 1-1 of 1 results found. %I A061906 %S A061906 1,1,1,1,1,1,1,1,1,1,1,1,21,38,18,35,17,16,14,9,1,12,1,7,29,21,19,37,9, %T A061906 8,1,14,66,1,8,15,7,3,13,15,1,16,6,23,1,13,9,3,44,7,1,19,13,4,518,1,11, %U A061906 3,4,13,1,442,7,4,33,9,1,11,4,6,1,845,88,4,3,7,287,1,11,6,1,12345679,8 %N A061906 Obtain m by omitting trailing zeros from n; a(n) = smallest k such that k*m is a palindrome. %C A061906 Every positive integer is a factor of a palindrome, unless it is a multiple of 10 (D. G. Radcliffe, see Links). %C A061906 Every integer n has a multiple of the form 99...9900...00. To see that n has a multiple that's a palindrome (allowing 0's on the left) with even digits, let 9n divide 99...9900...00; then n divides 22...2200...00. - Dean Hickerson, Jun 29, 2001. %H A061906 P. De Geest, Smallest multipliers to make a number palindromic. %e A061906 For n = 30 we have m = 3, 1*m = 3 is a palindrome, so a(30) = 1. For n = m = 12 the smallest palindromic multiple is 21*m = 252, so a(12) = 21. %o A061906 (ARIBAS): stop := 20000000; for n := 0 to maxarg do k := 1; test := true; while test and k < stop do mp := omit_trailzeros(n)*k; if test := mp <> int_reverse(mp) then inc(k); end; end; if k < stop then write(k, " "); else write(-1," "); end; end; %Y A061906 Cf. A050782, A062293, A061915, A061916, A061816. Values of k*m are given in A061906. %Y A061906 Sequence in context: A083567 A109211 A050782 this_sequence A139768 A072708 A102478 %Y A061906 Adjacent sequences: A061903 A061904 A061905 this_sequence A061907 A061908 A061909 %K A061906 base,easy,nonn %O A061906 0,13 %A A061906 Klaus Brockhaus (klaus-brockhaus(AT)t-online.de), Jun 25 2001 Search completed in 0.001 seconds