Search: id:A062938
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%I A062938
%S A062938 1,25,121,361,841,1681,3025,5041,7921,11881,17161,24025,32761,43681,
%T A062938 57121,73441,93025,116281,143641,175561,212521,255025,303601,358801,
%U A062938 421201,491401,570025,657721,755161,863041,982081,1113025,1256641
%N A062938 Squares of the form n(n+1)(n+2)(n+3) +1 = (n^2 +3n + 1)^2.
%C A062938 a(n) = product of first four terms of an arithmetic progression + n^4, 
               where the first term is 1 and the common difference is n. E.g. a(1) 
               = 1*2*3*4 +1^4 =25, a(4) = 1*5*9*13 + 4^4= 841 etc. - Amarnath Murthy 
               (amarnath_murthy(AT)yahoo.com), Sep 19 2003
%H A062938 Harry J. Smith, <a href="b062938.txt">Table of n, a(n) for n=0,...,1000</
               a>
%F A062938 a(n+1)=Numerator of ((n + 2)! + (n - 2)!)/(n!) n=3,4,5,... - Artur Jasinski 
               (grafix(AT)csl.pl), Jan 09 2007
%e A062938 2*3*4*5 + 1 = 121 = 11^2.
%t A062938 Table[Numerator[((n + 2)! + (n - 2)!)/(n!)], {n, 3, 30}] - Artur Jasinski 
               (grafix(AT)csl.pl), Jan 09 2007
%o A062938 (PARI) j=[]; for(n=0,70,j=concat(j,(n^2+3*n+1)^2)); j
%o A062938 (PARI) { for (n=0, 1000, write("b062938.txt", n, " ", (n^2 + 3*n + 1)^2) 
               ) } [From Harry J. Smith (hjsmithh(AT)sbcglobal.net), Aug 14 2009]
%Y A062938 Sequence in context: A083509 A031151 A016970 this_sequence A141722 A090159 
               A025283
%Y A062938 Adjacent sequences: A062935 A062936 A062937 this_sequence A062939 A062940 
               A062941
%K A062938 nonn
%O A062938 0,2
%A A062938 Amarnath Murthy (amarnath_murthy(AT)yahoo.com), Jul 05 2001
%E A062938 More terms from Jason Earls (zevi_35711(AT)yahoo.com), Harvey P. Dale 
               (hpd1(AT)nyu.edu) and Dean Hickerson (dean.hickerson(AT)yahoo.com), 
               Jul 06 2001

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