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Search: id:A063574
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| A063574 |
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Number of steps to reach an integer == 1 (mod 4) when iterating the map n -> 3n/2 if n even or (3n+1)/2 if n odd. |
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+0
4
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| 0, 2, 1, 2, 0, 1, 2, 4, 0, 4, 1, 3, 0, 1, 3, 4, 0, 2, 1, 2, 0, 1, 2, 3, 0, 3, 1, 7, 0, 1, 4, 6, 0, 2, 1, 2, 0, 1, 2, 5, 0, 6, 1, 3, 0, 1, 3, 5, 0, 2, 1, 2, 0, 1, 2, 3, 0, 3, 1, 4, 0, 1, 5, 6, 0, 2, 1, 2, 0, 1, 2, 4, 0, 4, 1, 3, 0, 1, 3, 4, 0, 2, 1, 2, 0, 1, 2, 3, 0, 3, 1, 5, 0, 1, 4, 5, 0, 2, 1, 2, 0, 1, 2, 7, 0
(list; graph; listen)
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OFFSET
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1,2
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REFERENCES
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L. Flatto, Z-numbers and beta-transformations, in Symbolic dynamics and its applications (New Haven, CT, 1991), 181-201, Contemp. Math., 135, Amer. Math. Soc., Providence, RI, 1992.
K. Mahler, An unsolved problem on the powers of 3/2, J. Austral. Math. Soc. 8 1968 313-321.
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FORMULA
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For odd n: a(n)=A007814(n+1), for even n: A007814(n) steps until an odd number is reached, which leads directly to the formula: with b(n)=A007814(n) (binary carry sequence) a(n)=b(n)+b((3^b(n)*n/2^b(n)+1)/2) - Lambert Herrgesell (zero815(AT)googlemail.com) and Lambert Klasen (lambert.klasen(AT)gmx.net), Apr 24 2006. Hence in particular, a(n) is well-defined.
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EXAMPLE
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8 -> 12 -> 18 -> 27 -> 41 takes 4 steps so a(8) = 4.
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PROGRAM
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PARI {stop=1000; for(n=1, 105, c=0; k=n; while((k%4)!=1&&c<stop, k=if(k%2==0, 3*k/2, (3*k+1)/2); c++); print1(if(c<stop, c, -1), ", "))}
(PARI) b(n)=valuation(n, 2); a(n)=b(n)+b((3^b(n)*n/2^b(n)+1)/2) - Lambert Herrgesell (zero815(AT)googlemail.com) and Lambert Klasen (lambert.klasen(AT)gmx.net), Apr 24 2006
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CROSSREFS
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Cf. A007494.
Sequence in context: A114004 A049986 A137289 this_sequence A144515 A028933 A143352
Adjacent sequences: A063571 A063572 A063573 this_sequence A063575 A063576 A063577
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KEYWORD
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easy,nice,nonn
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AUTHOR
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N. J. A. Sloane (njas(AT)research.att.com), Sep 23 2002
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EXTENSIONS
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Extended by Klaus Brockhaus (klaus-brockhaus(AT)t-online.de), Sep 23 2002
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