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Search: id:A071912
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| A071912 |
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a(0) = 0, a(1) = 1; to get a(n+1) for n >= 1, let m = a(n) and consider in turn the numbers k = m-1, m-2, ..., 2, 1, m+1, m+2, m+3, ... until reach a k such that GCD(m,k) = 1 and m/k is different from all a(i)/a(i+1) for i = 0, ...,n-1. |
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| 0, 1, 1, 2, 1, 3, 2, 3, 1, 4, 3, 4, 1, 5, 4, 5, 3, 5, 2, 5, 1, 6, 5, 6, 1, 7, 6, 7, 5, 7, 4, 7, 3, 7, 2, 7, 1, 8, 7, 8, 5, 8, 3, 8, 1, 9, 8, 9, 7, 9, 5, 9, 4, 9, 2, 9, 1, 10, 9, 10, 7, 10, 3, 10, 1, 11, 10, 11, 9, 11, 8, 11, 7, 11, 6, 11, 5, 11, 4, 11, 3, 11, 2, 11, 1, 12, 11, 12, 7, 12
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