1,2

Same as the number of elements of GF(7^n) with trace 2 and subtrace 3. Same as the number of elements of GF(7^n) with trace 3 and subtrace 5. Same as the number of elements of GF(7^n) with trace 4 and subtrace 5. Same as the number of elements of GF(7^n) with trace 5 and subtrace 3. Same as the number of elements of GF(7^n) with trace 6 and subtrace 6.

F. Ruskey, Number of Elements of GF(7^n) with given trace and subtrace

a(3;1,6)=6. Let GF(7^3) be defined by the field extension GF(7)[x]/( 3+b^2+b^3 ). The six elements of GF(7^3) with trace 1 and subtrace 6 are { 1+2b, 2+5b, 1+3b+b^2, 4+5b+b^2, 6+2b+6b^2, 2+4b+6b^2 }.

Cf. A074014, A074015, A074016, A074017, A074018, A074019, A074020, A074021, A074022.

Sequence in context: A122593 A153450 A084123 this_sequence A000146 A014070 A132525

Adjacent sequences: A074020 A074021 A074022 this_sequence A074024 A074025 A074026

easy,nonn

Frank Ruskey, Nate Kube (fruskey(AT)cs.uvic.ca), Aug 19 2002