Search: id:A074867 Results 1-1 of 1 results found. %I A074867 %S A074867 1,1,2,3,5,8,13,11,4,5,9,14,13,7,10,7,7,14,11,5,6,11,7,8,15,13,8,11,9, %T A074867 10,9,9,18,17,15,12,7,9,16,15,11,6,7,13,10,3,3,6,9,15,14,9,13,12,5,7,12, %U A074867 9,11,10,1,1,2,3,5,8,13,11,4,5,9,14,13,7,10,7,7,14,11,5,6,11,7,8,15,13 %N A074867 a(n)=M[a(n-1)]+M[a(n-2)] where a(0)=a(1)=1 and M(n) is the product of the digits of n in base 10. %C A074867 Periodic with least period 60. - Christopher N. Swanson (cswanson(AT)ashland.edu), Jul 22 2003 %C A074867 The digital product analogue (in base 10) of the Fibonacci recurrence. - Hieronymus Fischer (Hieronymus.Fischer(AT)gmx.de), Jul 01 2007 %C A074867 a(n) and Fib(n)=A000045(n) are congruent modulo 10 which implies that (a(n) mod 10) is equal to (Fib(n) mod 10) = A003893(n). Thus (a(n) mod 10) is periodic with the Pisano period A001175(10)=60. - Hieronymus Fischer (Hieronymus.Fischer(AT)gmx.de), Jul 01 2007 %C A074867 a(n)==A131297(n) modulo 10 (A131297(n)=digital sum analogue base 11 of the Fibonacci recurrence). - Hieronymus Fischer (Hieronymus.Fischer(AT)gmx.de), Jul 01 2007 %C A074867 For general bases p>1, we have the inequality 1<=a(n)<=2p-2 (for n>0). Actually, a(n)<=18. - Hieronymus Fischer (Hieronymus.Fischer(AT)gmx.de), Jul 01 2007 %F A074867 a(n)=a(n-1)+a(n-2)-10*(floor(a(n-1)/10)+floor(a(n-2)/10)). This is valid, since a(n)<100. - Hieronymus Fischer (Hieronymus.Fischer(AT)gmx.de), Jul 01 2007 %F A074867 a(n)=ds_10(a(n-1))+ds_10(a(n-2))-(floor(a(n-1)/10)+floor(a(n-2)/10)) where ds_10(x) is the digital sum of x in base 10. - Hieronymus Fischer (Hieronymus.Fischer(AT)gmx.de), Jul 01 2007 %F A074867 a(n)=(a(n-1)mod 10)+(a(n-2)mod 10)=A010879(a(n-1))+A010879(a(n-2)). - Hieronymus Fischer (Hieronymus.Fischer(AT)gmx.de), Jul 01 2007 %F A074867 a(n)=A131297(n) if A131297(n)<=10. - Hieronymus Fischer (Hieronymus.Fischer(AT)gmx.de), Jul 01 2007 %F A074867 a(n)=Fib(n)-10*sum{1