Search: id:A075193 Results 1-1 of 1 results found. %I A075193 %S A075193 1,3,4,7,11,18,29,47,76,123,199,322,521,843,1364,2207,3571,5778,9349,15127, %T A075193 24476,39603,64079,103682,167761,271443,439204,710647,1149851,1860498, 3010349, %U A075193 4870847,7881196,12752043,20633239,33385282,54018521,87403803,141422324 %V A075193 1,-3,4,-7,11,-18,29,-47,76,-123,199,-322,521,-843,1364,-2207,3571,-5778, 9349,-15127, %W A075193 24476,-39603,64079,-103682,167761,-271443,439204,-710647,1149851,-1860498, 3010349, %X A075193 -4870847,7881196,-12752043,20633239,-33385282,54018521,-87403803,141422324 %N A075193 "Inverted" Lucas numbers (see Comments). %C A075193 The g.f. is obtained inserting 1/x into the g.f. of Lucas sequence and dividing by x. The closed form is a(n)=(-1)^n*a^(n+1)+(-1)^n*b^(n+1), where a=golden ratio and b=1-a, so that a(n)=(-1)^n*L(n+1), L(n)=Lucas numbers. %H A075193 Index entries for sequences related to linear recurrences with constant coefficients %H A075193 Tanya Khovanova, Recursive Sequences %F A075193 a(n)=-a(n-1)+a(n-2), a(0)=1, a(1)=-3. G.f.: (1-2x)/(1+x-x^2). %F A075193 a(n) = term (1,1) in the 1x2 matrix [1,-2] . [-1,1; 1,0]^n. [From Alois P. Heinz (heinz(AT)hs-heilbronn.de), Jul 31 2008] %p A075193 (Maple) a := n -> (Matrix([[1,-2]]).Matrix([[-1,1], [1,0]])^(n))[1,1]; seq (a(n), n=0..38); [From Alois P. Heinz (heinz(AT)hs-heilbronn.de), Jul 31 2008] %t A075193 CoefficientList[Series[(1 - 2z)/(1 + z - z^2), {z, 0, 40}], z] %Y A075193 Cf. A000032. %Y A075193 Sequence in context: A100581 A093090 A000204 this_sequence A042433 A024319 A041209 %Y A075193 Adjacent sequences: A075190 A075191 A075192 this_sequence A075194 A075195 A075196 %K A075193 easy,sign %O A075193 0,2 %A A075193 Mario Catalani (mario.catalani(AT)unito.it), Sep 07 2002 Search completed in 0.001 seconds