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Search: id:A077113
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| A077113 |
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Number of integer cubes <= n^2. |
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+0
4
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| 1, 2, 2, 3, 3, 3, 4, 4, 5, 5, 5, 5, 6, 6, 6, 7, 7, 7, 7, 8, 8, 8, 8, 9, 9, 9, 9, 10, 10, 10, 10, 10, 11, 11, 11, 11, 11, 12, 12, 12, 12, 12, 13, 13, 13, 13, 13, 14, 14, 14, 14, 14, 14, 15, 15, 15, 15, 15, 15, 16, 16, 16, 16, 16, 17, 17, 17, 17, 17, 17, 17, 18, 18, 18, 18, 18, 18, 19
(list; graph; listen)
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OFFSET
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0,2
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COMMENT
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a(n) = least number m such that m^3 > n^2. - Zak Seidov (zakseidov(AT)yahoo.com), May 03 2005
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FORMULA
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a(n) = floor(n^(2/3))+1.
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EXAMPLE
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Cubes <= 10^2: 0, 1, 8, 27 and 64, hence a(10)=5;
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MATHEMATICA
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Table[Floor[n^(2/3) + 1], {n, 0, 100}] - Zak Seidov (zakseidov(AT)yahoo.com), May 03 2005
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CROSSREFS
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Cf. A077106, A026409, A026414, A054071, A077121.
Sequence in context: A060144 A107347 A163127 this_sequence A143796 A057362 A085269
Adjacent sequences: A077110 A077111 A077112 this_sequence A077114 A077115 A077116
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KEYWORD
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nonn
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AUTHOR
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Reinhard Zumkeller (reinhard.zumkeller(AT)gmail.com), Oct 29 2002
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EXTENSIONS
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Edited by N. J. A. Sloane (njas(AT)research.att.com), Aug 29 2008 at the suggestion of R. J. Mathar
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