Search: id:A078188
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%I A078188
%S A078188 1,2,3,4,5,6,7,8,9,90,99,96,26,28,285,528,85,18,19,20,21,22,23,24,25,
%T A078188 52,27,28,29,90,93,32,33,34,35,36,37,38,39,40,41,42,43,44,45,46,47,48,
%U A078188 49,50,51,52,53,54,55,56,57,58,59,60,61,62,63,64,65,66,67,68,69,70,71
%N A078188 a(1) = 1; for n > 1 take the digits of a(n-1) one after the other and 
               remove one occurrence of this digit from the digits of m = k*n (k 
               > 0) if possible; a(n) is the smallest multiple m of n which has 
               the least number of remaining digits (counted with multiplicity).
%e A078188 For n = 10 we have a(n-1) = a(9) = 9; removing 9 from 9*n = 9*10 = 90 
               results in one remaining digit (i.e. 0) and for every smaller multiple 
               of 10 (i.e. 10, 20, ..., 80) there are two remaining digits, so a(10) 
               = 90. For n = 20 we have a(n-1) = a(19) = 19; for 1*n = 1*20 = 20 
               no digit is removed and two digits remain and there is no multiple 
               of 20 which has less than two remaining digits (for 100 twice the 
               digit 0), so a(20) = 20.
%Y A078188 Sequence in context: A032799 A160343 A024664 this_sequence A061805 A061219 
               A071271
%Y A078188 Adjacent sequences: A078185 A078186 A078187 this_sequence A078189 A078190 
               A078191
%K A078188 base,nonn
%O A078188 1,2
%A A078188 Amarnath Murthy (amarnath_murthy(AT)yahoo.com), Nov 21 2002
%E A078188 Edited, corrected and extended by Klaus Brockhaus (klaus-brockhaus(AT)t-online.de), 
               Dec 03 2002

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