Search: id:A079101
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%I A079101
%S A079101 0,1,0,0,0,1,1,0,1,0,1,1,1,0,0,1,0,0,1,1,1,1,0,1,1,0,0,0,0,0,1,0,1,0,0,
%T A079101 0,0,1,1,1,0,1,0,0,1,0,1,1,0,1,1,1,1,1,0,0,0,1,0,0,0,0,0,0,0,1,1,0,0,0,
%U A079101 1,1,1,1,1,1,0,1,0,1,0,0,1,1,0,0,1,0,1,0,1,0,1,1,0,0,1,1,0,1,1,0,1,0,0
%N A079101 A repetition-resistant sequence.
%C A079101 a(n) = 0 or 1, chosen so as to maximize the number of different subsequences
that are formed.
%C A079101 a(n+1)=1 if and only if (a(1),a(2),...,a(n),0), but not (a(1),a(2),...,
a(n),1), has greater length of longest repeated segment than (a(1),
a(2),...,a(n)) has.
%C A079101 In Feb, 2003, Alejandro Dau solved Problem 3 on the Unsolved Problems
and Rewards website, thus establishing that every binary word occurs
infinitely many times in this sequence.
%C A079101 Klaus Sutmer remarks (Jun 26 2006) that this sequence is very similar
to the Ehrenfeucht-Mycielski sequence A007061. Both sequences have
every finite binary word as a factor; in fact, essentially the same
proof works for both sequences.
%D A079101 C. Kimberling, Problem 2289, Crux Mathematicorum 23 (1997) 501.
%H A079101 A. Dau Secuencia Maximizadora de Subcadenas (Interactive
Javagenerator of repetition-resistant sequences).
%H A079101 C. Kimberling,
Unsolved Problems and Rewards.
%e A079101 a(7)=1 because (0,1,0,0,0,1,0) has repeated segment (0,1,0) of length
3, whereas (0,1,0,0,0,1,1) has no repeated segment of length 3.
%Y A079101 Cf. A079136, A079335, A079336, A079337, A079338, A007061.
%Y A079101 Sequence in context: A134667 A117943 A096268 this_sequence A076478 A091444
A091447
%Y A079101 Adjacent sequences: A079098 A079099 A079100 this_sequence A079102 A079103
A079104
%K A079101 nonn
%O A079101 1,1
%A A079101 Clark Kimberling (ck6(AT)evansville.edu), Jan 03 2003
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