Search: id:A080097 Results 1-1 of 1 results found. %I A080097 %S A080097 0,3,8,24,63,168,440,1155,3024,7920,20735,54288,142128,372099,974168, %T A080097 2550408,6677055,17480760,45765224,119814915,313679520,821223648, %U A080097 2149991423,5628750624,14736260448,38580030723,101003831720 %N A080097 Fibonacci(n+2)^2 - 1. %C A080097 a(n), a(n)+1 and a(n)+2 are consecutive members of A049997. %F A080097 If n is odd, then a(n) = F(n+1)F(n+3) = F(n)F(n+4)-2, else a(n) = F(n)F(n+4) = F(n+1)F(n+3)-2, where F(n) = Fibonacci numbers (A000045). %F A080097 (1/5) {Lucas(2n+4) - 2(-1)^n - 5}. %F A080097 G.f.: (3x+2x^2-x^3)/(1-x^2)(1-2x-2x^2+x^3)). %t A080097 CoefficientList[Series[(3x+2x^2-x^3)/(1-x^2)(1-2x-2x^2+x^3)), {x, 0, 35}], x] %Y A080097 Equals A007598(n+2) - 1. Cf. A064831, A059840. %Y A080097 Sequence in context: A084920 A026556 A096001 this_sequence A096886 A056332 A091588 %Y A080097 Adjacent sequences: A080094 A080095 A080096 this_sequence A080098 A080099 A080100 %K A080097 easy,nonn %O A080097 0,2 %A A080097 Mario Catalani (mario.catalani(AT)unito.it), Jan 29 2003 %E A080097 Edited by Ralf Stephan, May 15 2005 Search completed in 0.001 seconds