%I A081769
%S A081769 5,13,18,23,25,30,38,43,45,53,58,60,65,70,78,83,85,93,98,103,105,110,
%T A081769 118,120,125,133,138,140,145,150,158,163,165,173,178,183,185,190,198,
%U A081769 203,205,213,218,220,225,230,238,240,245,253,258,263,265,270,278,280
%N A081769 a(n)-th term of the continued fraction for sum(k>=0,1/2^(2^k)) is 2.
%F A081769 a(n)=5*n + 0 or + 3 and it appears that a(n)=5*n+3*A073089(n+2)
%e A081769 The continued fraction for sum(k>=0,1/2^(2^k)) is : 1, 1, 1, 1, 2, 1, 
               1, 1, 1, 1, 1, 1, 2, 1... hence a(1)=5
%Y A081769 Cf. A006466, A073089.
%Y A081769 Sequence in context: A125146 A051900 A120062 this_sequence A101864 A022138 
               A028274
%Y A081769 Adjacent sequences: A081766 A081767 A081768 this_sequence A081770 A081771 
               A081772
%K A081769 easy,nonn
%O A081769 1,1
%A A081769 Benoit Cloitre (benoit7848c(AT)orange.fr), Apr 09 2003