Search: id:A082410 Results 1-1 of 1 results found. %I A082410 %S A082410 0,1,1,0,1,1,0,0,1,1,1,0,0,1,0,0,1,1,1,0,1,1,0,0,0,1,1,0,0,1,0,0,1,1,1, %T A082410 0,1,1,0,0,1,1,1,0,0,1,0,0,0,1,1,0,1,1,0,0,0,1,1,0,0,1,0,0,1,1,1,0,1,1, %U A082410 0,0,1,1,1,0,0,1,0,0,1,1,1,0,1,1,0,0,0,1,1,0,0,1,0,0,0,1,1,0,1,1,0,0,1 %N A082410 a(1)=0 and a(n) is built with the rule: for any k>=0, if a(1),a(2),......, a(2^k+1) are known next 2^k terms are given as follows: a(2k^+1+i)=1-a(2^k+1-i) for 1<=i<=2^k %C A082410 It seems that a(n) is A014577 shifted right twice. %C A082410 Complement of characteristic function of A060833. %F A082410 n>=2 sum(k=1, n, a(k))=(n+A037834(n-1))/2 %e A082410 3 first terms are 0,1,1 therefore a(4)=a(3+1)=1-a(3-1)=1-a(2)=0, a(5)=a(3+2)=1-a(3-2)=1-a(1)=1 and sequence begins 0,1,1,0,1,... %Y A082410 Sequence in context: A103226 A080886 A083924 this_sequence A094217 A092220 A011655 %Y A082410 Adjacent sequences: A082407 A082408 A082409 this_sequence A082411 A082412 A082413 %K A082410 nonn %O A082410 1,1 %A A082410 Benoit Cloitre (benoit7848c(AT)orange.fr), Apr 24 2003 Search completed in 0.001 seconds