Search: id:A086105
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%I A086105
%S A086105 0,1,1,1,1,2,2,4,6,24,4738381338321616896,4738381338321616920,
%T A086105 22452257707354557353808363243511480320
%N A086105 Adding, multiplying and exponentiating cycle of the previous two terms 
               similar to A039941.
%F A086105 a(1)=0, a(2)=1, a(n): if n mod 3 is 0: a(n)=a(n-2) + a(n-1), if n mod 
               3 is 1: a(n)=a(n-2) * a(n-1), if n mod 3 is 2: a(n)=a(n-2)^a(n-1).
%e A086105 a(11) = a(9)^a(10)=6^24 because 11 mod 3 is 2.
%Y A086105 Cf. A039941.
%Y A086105 Sequence in context: A069925 A080611 A072707 this_sequence A084701 A113815 
               A110946
%Y A086105 Adjacent sequences: A086102 A086103 A086104 this_sequence A086106 A086107 
               A086108
%K A086105 easy,nonn
%O A086105 1,6
%A A086105 Anthony Peterson (civ2buf(AT)ricochet.com), Jul 09 2003
%E A086105 The next 2 terms are (6^24)^((6^24)*(6^24+24)) and (6^24)^((6^24) * (6^24 
               + 24)) + (6^24) * (6^24 + 24).

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