Search: id:A086594 Results 1-1 of 1 results found. %I A086594 %S A086594 2,8,66,536,4354,35368,287298,2333752,18957314,153992264,1250895426, %T A086594 10161155672,82540140802,670482282088,5446398397506,44241669462136, %U A086594 359379754094594,2919279702218888 %N A086594 a(n)=8a(n-1)+a(n-2), starting with a(0)=2 and a(1)=8. %C A086594 Harmonious sequence, build on the number 8.1231056... %C A086594 a(n+1)/a(n) converges to 4+sqrt(17). a(0)/a(1)=1/4; a(1)/a(2)=8/66; a(2)/ a(3)=66/536; a(3)/a(4)=536/4354;...etc. Lim a(n)/a(n+1)as n approaches infinity=0.123105625...=1/(4+sqrt(17))=sqrt(17)-4. %H A086594 Index entries for sequences related to linear recurrences with constant coefficients %H A086594 Tanya Khovanova, Recursive Sequences %H A086594 Index entries for recurrences a(n) = k*a(n - 1) +/- a(n - 2) %F A086594 a(n)=(4+sqrt(17))^n+(4-sqrt(17))^n. %F A086594 O.g.f: 2*(-1+4*x)/(-1+8*x+x^2) . - R. J. Mathar (mathar(AT)strw.leidenuniv.nl), Dec 02 2007 %e A086594 a(4)=4354=8a(3)+a(2)=8*536+66=(4+sqrt(17))^4+(4-sqrt(17))^4=4353.9997703+ %e A086594 0.0002297=4354. %Y A086594 Cf. A003285. %Y A086594 Sequence in context: A009602 A011836 A100623 this_sequence A132219 A023164 A053922 %Y A086594 Adjacent sequences: A086591 A086592 A086593 this_sequence A086595 A086596 A086597 %K A086594 easy,nonn %O A086594 0,1 %A A086594 Nikolay V. Kosinov (kosinov(AT)unitron.com.ua), Sep 11 2003 Search completed in 0.001 seconds