Search: id:A088435
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%I A088435
%S A088435 3,2,2,1,2,3,2,1,3,2,1,2,2,3,2,1,3,2,2,1,2,3,1,2,3,2,1,2,2,3,2,1,3,2,2,
%T A088435 1,2,3,2,1,3,2,1,2,2,3,1,2,3,2,2,1,2,3,1,2,3,2,1,2,2,3,2,1,3,2,2,1,2,3,
%U A088435 2,1,3,2,1,2,2,3,2,1,3,2,2,1,2,3,1,2,3,2,1,2,2,3,1,2,3,2,2,1,2,3,2,1,3
%N A088435 1/2 + half of the (n+1)-st component of the continued fraction expansion 
               of sum(k>=1,1/3^(2^k)).
%C A088435 To construct the sequence use the rule : a(1)=3, then a(a(1)+a(2)+...+a(n)+1)=2+(-1)^n 
               and fill in any undefined place with 2.
%F A088435 a(n)=(1/2)*(1+A004200(n+1)); a(a(1)+a(2)+...+a(n)+1)=2+(-1)^n
%e A088435 Example to illustrate the comment : a(a(1)+1)=a(4)=2+(-1)^1=1 and a(2), 
               a(3) are undefined. The rule forces a(2)=a(3)=2.
%Y A088435 Cf. A088431.
%Y A088435 Sequence in context: A154395 A152159 A090341 this_sequence A074976 A068448 
               A054081
%Y A088435 Adjacent sequences: A088432 A088433 A088434 this_sequence A088436 A088437 
               A088438
%K A088435 nonn
%O A088435 1,1
%A A088435 Benoit Cloitre (benoit7848c(AT)orange.fr), Nov 08 2003 Ben.

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