%I A092079
%S A092079 1,1,1,0,1,0,1,1,0,0,1,1,1,0,1,0,1,0,0,0,0,1,0,1,0,1,0,0,1,0,0,0,1,0,0,
%T A092079 0,0,0,0,1,1,1,1,1,1,0,1,1,0,0,0,1,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,1,0,
%U A092079 1,0,1,1,0,1,0,1,0,0,1,1,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0
%N A092079 Characteristic array marking partitions of m whose parts are exponents
of partitions of n into m parts.
%C A092079 With N=A000217(n-1) + m, where A000217(n-1) is the largest triangular
number less than N, a(N,k)=1 if there is at least one partition of
n into m parts which has the parts of the k-th partition of m (in
Abramowitz-Stegun order) as exponents. Otherwise a(N,k)=0.
%C A092079 The sequence of row lengths of this array is p(m)= A000041(m) (number
of partitions of m) and m is determined from N (the row index) as
explained above. It is [1,1,2,1,2,3,1,2,3,5,1,2,3,5,7,1,2,3,5,7,11,
...]=A092080(N), N>=1.
%C A092079 One can find the (n,m; k) numbers for the p-th entry (p>2) of the sequence
as follows: p= a(n-1) + b(m-1) + k, where a(n-1) := A085360(n-1)
is the largest number from the numbers A085360 less than p and b(m-1)=A026905(m-1)
is the largest number from the numbers A026905 less than p-a(n-1).
p=1 belongs to (1,1;1) and p=2 to (2,1;1).
%H A092079 M. Abramowitz and I. A. Stegun, eds., <a href="http://www.nrbook.com/
abramowitz_and_stegun/">Handbook of Mathematical Functions</a>, National
Bureau of Standards, Applied Math. Series 55, Tenth Printing, 1972
[alternative scanned copy].
%H A092079 M. Abramowitz and I. A. Stegun, eds., <a href="http://www.convertit.com/
Go/ConvertIt/Reference/AMS55.ASP">Handbook of Mathematical Functions</
a>, National Bureau of Standards Applied Math. Series 55, Tenth Printing,
1972, pp. 831-2.
%H A092079 W. Lang, <a href="http://www-itp.physik.uni-karlsruhe.de/~wl/EISpub/A092079.text">
First 36 rows and more comments</a>.
%e A092079 N=13 = 10 + 3 with 10=A000217(4), hence n=5 and m=3.
%e A092079 N=10 = 6 + 4 with 6=A000217(3), hence n=4 and m=4.
%e A092079 The sequence entry nr. p=16, which is 0, belongs to (n=4,m=3; k=3) because
16 = 10 + 3 + 3 with 10=A085360(3), hence n=4 and 3=A026905(2), hence
m=3.
%e A092079 a(N=13,k=3)=0: There is no partition of 5 into 3 parts which has as exponents
1,1,1, the parts of the third (k=3) partition of 3.
%e A092079 a(N=13,k=2)=1, n=5, m=3; there is a partition of 5 into 3 parts, which
has the parts of the second (k=2) partitions of 3, i.e. 1,2, as exponents.
In fact there are two such partitions, namely [1^2, 3^1] and [1^1,
2^2].
%Y A092079 Cf. A092078 (with multiplicities).
%Y A092079 Sequence in context: A104338 A071023 A132194 this_sequence A139312 A071041
A140074
%Y A092079 Adjacent sequences: A092076 A092077 A092078 this_sequence A092080 A092081
A092082
%K A092079 nonn,easy,tabf
%O A092079 1,1
%A A092079 Wolfdieter Lang (wolfdieter.lang_AT_physik_DOT_uni-karlsruhe_DOT_de),
Mar 19 2004
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