Search: id:A092876 Results 1-1 of 1 results found. %I A092876 %S A092876 1,1,1,2,1,0,1,1,1,2,0,0,2,2,3,2,6,3,1,2,2,2,4,0,2,5,7,8,6,16,7,1,6,6, 7, %T A092876 10,1,2,11,14,17,12,34,16,3,12,11,12,22,1,6,24,30,36,25,70,32,6,25,24, 26,42, %U A092876 2,10,45,56,68,48,132,60,12,45,43,46,78,4,22,84,106,126,89,242,110,20, 84,80 %V A092876 1,-1,1,-2,1,0,1,1,-1,-2,0,0,2,2,-3,2,-6,3,1,2,2,-2,-4,0,-2,5,7,-8,6,-16, 7,1,6,6,-7, %W A092876 -10,1,-2,11,14,-17,12,-34,16,3,12,11,-12,-22,1,-6,24,30,-36,25,-70,32, 6,25,24,-26,-42, %X A092876 2,-10,45,56,-68,48,-132,60,12,45,43,-46,-78,4,-22,84,106,-126,89,-242, 110,20,84,80 %N A092876 Coefficients of a solution to a functional equation. %C A092876 Euler transform of period 13 sequence [ -1,1,-1,-1,1,1,1,1,-1,-1,1,-1, 0,...]. %F A092876 G.f. A(x) satisfies 0=f(A(x), A(x^2)) where f(u, v)=u^2-v+u*v^3+u^3*v^2+2*u*v*(1-u+v+u*v). %F A092876 G.f. A(x) satisfies 0=f(A(x), A(x^3)) where f(u, v)=u^3*v*(3+3*v+v^2) +3*u^2*v*(v^2+v-1) +u*v*(1-3*v+3*v^2) -(u^4+v^4) %F A092876 G.f.: x Product_{k>0} (1-x^k)^kronecker(13, k). %o A092876 (PARI) {a(n)=if(n<1, 0, n--; polcoeff( prod(k=1,n,(1-x^k)^kronecker(13, k),1+x*O(x^n)), n))} /* Michael Somos Oct 24 2005 */ %o A092876 (PARI) {a(n)=local(A,u,v); if(n<0,0,A=x; for(k=2,n,u=A+x*O(x^k); v=subst(u, x,x^2); A-=x^k*polcoeff(u^2-v+u*v^3+u^3*v^2+2*u*v*(1-u+v+u*v),k+1)/ 2); polcoeff(A,n))} %Y A092876 Sequence in context: A130654 A053259 A143842 this_sequence A024940 A054635 A003137 %Y A092876 Adjacent sequences: A092873 A092874 A092875 this_sequence A092877 A092878 A092879 %K A092876 sign %O A092876 1,4 %A A092876 Michael Somos, Mar 09 2004 Search completed in 0.001 seconds