%I A094778
%S A094778 0,5,4,2,5,2,2,2,2,2,2,2,5,2,2,2,4,4,15,5,2,4,4,2,5,2,4,4,2,5,2,2,2,2,
7,
%T A094778 2,4,5,10,2,7,2,4,7,8,2,2,5,5,8,5,13,8,2,7,8,13,10,4,2,4,2,4,4,8,4,4,2,
%U A094778 5,2,2,2,2,2,2,4,2,5,5,2,2,24,10,2,4,2,26,5,2,2,4,10,2,5,2,4,70,4,5,5,
5
%N A094778 "Dropping time" in juggler sequence problem starting at 2n+1 (number
of steps to reach a lower number than starting value).
%C A094778 If the starting value is even then of course the next step in the trajectory
is smaller.
%e A094778 9 -> 27 -> 140 -> 11 -> 36 -> 6, taking 5 steps, so a(4) = 5.
%Y A094778 Cf. A007320, A094683.
%Y A094778 Sequence in context: A090462 A081749 A074825 this_sequence A097960 A019712
A020799
%Y A094778 Adjacent sequences: A094775 A094776 A094777 this_sequence A094779 A094780
A094781
%K A094778 easy,nonn
%O A094778 0,2
%A A094778 Jason Earls (zevi_35711(AT)yahoo.com), Jun 10 2004
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