|
Search: id:A095715
|
|
|
| A095715 |
|
Triangle of numbers obtained by reversing the first n digits of 1/phi and juxtaposing (phi denotes the golden ratio: A001622). |
|
+0 1
|
|
| 0, 6, 0, 1, 6, 0, 8, 1, 6, 0, 0, 8, 1, 6, 0, 3, 0, 8, 1, 6, 0, 3, 3, 0, 8, 1, 6, 0, 9, 3, 3, 0, 8, 1, 6, 0, 8, 9, 3, 3, 0, 8, 1, 6, 0, 8, 8, 9, 3, 3, 0, 8, 1, 6, 0, 7, 8, 8, 9, 3, 3, 0, 8, 1, 6, 0, 4, 7, 8, 8, 9, 3, 3, 0, 8, 1, 6, 0, 9, 4, 7, 8, 8, 9, 3, 3, 0, 8, 1, 6, 0, 8, 9, 4, 7, 8, 8, 9, 3, 3, 0, 8, 1, 6, 0
(list; table; graph; listen)
|
|
|
OFFSET
|
1,2
|
|
|
LINKS
|
Paul Cooijmans, Numbers, Item 16.
Paul Cooijmans, Short Test For Genius, Item 32.
|
|
EXAMPLE
|
0; 6,0; 1,6,0; 8,1,6,0; 0,8,1,6,0; 3,0,8,1,6,0; 3,3,0,8,1,6,0; 9,3,3,0,8,1,6,0;... (reverse order of 0.6; 0.61; 0.618; 0.6180; 0.61803; 0.618033; 0.6180339;...)
|
|
PROGRAM
|
(PARI) a(n)=if(n<1, 0, default(realprecision, n+2); floor((-1/2+sqrt(5)/2)*10^(n-1))%10); b(n)=1+binomial(1+floor(1/2+sqrt(2*n)), 2)-n; for(n=1, 120, print1(a(b(n)), ", ")
|
|
CROSSREFS
|
Cf. A094214.
Cf. A095713.
Sequence in context: A011253 A049248 A094691 this_sequence A141108 A019846 A137943
Adjacent sequences: A095712 A095713 A095714 this_sequence A095716 A095717 A095718
|
|
KEYWORD
|
base,easy,nonn,tabl
|
|
AUTHOR
|
Herman Jamke (hermanjamke(AT)fastmail.fm), Jul 07 2004
|
|
|
Search completed in 0.002 seconds
|