Search: id:A098062
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%I A098062
%S A098062 13,29,53,173,229,293,733,1093,1229,1373,2029,2213,3253,4229,4493,5333,
%T A098062 7229,7573,9029,9413,10613,13229,13693,15629,18229,18773,21613,24029,
%U A098062 26573,27893,31333,33493,37253,41213,42853,46229,47093,54293,55229
%N A098062 Primes of the form n^2 + 4n + 8.
%C A098062 Or, primes that are equal to the mean of 7 consecutive squares. - Zak 
               Seidov (zakseidov(AT)gmail.com), Apr 14 2007
%C A098062 Sum of 7 consecutive squares starting with m^2 is equal to 7*(13 + 6*m 
               + m^2) and mean is (13 + 6*m + m^2)=(m+3)^2+4. Hence a(n)=A005473(n+1). 
               Note that only nonnegative m's are considered. - Zak Seidov (zakseidov(AT)gmail.com), 
               Apr 14 2007
%C A098062 a(n)==1 (mod 4).
%C A098062 a(n)= A005473(n+1). - Zak Seidov, Apr 12 2007
%e A098062 13=(0^2+...+6^2)/7, 29=(2^2+...+8^2)/7=29, 53=(4^2+...+10^2)/7=53.
%t A098062 Select[ Table[ n^2 + 4n + 8, {n, 240}], PrimeQ[ # ] &] (from Robert G. 
               Wilson v Sep 14 2004)
%o A098062 (PARI) for(n=0,240,if(isprime(p=n^2+4*n+8),print1(p,","))) (Klaus Brockhaus)
%Y A098062 Cf. A005473, A056899, A067201, A007591, A129389, A129412.
%Y A098062 Sequence in context: A010337 A162579 A090866 this_sequence A094481 A045637 
               A146743
%Y A098062 Adjacent sequences: A098059 A098060 A098061 this_sequence A098063 A098064 
               A098065
%K A098062 nonn
%O A098062 1,1
%A A098062 Giovanni Teofilatto (g.teofilatto(AT)tiscalinet.it), Sep 12 2004
%E A098062 Edited, corrected and extended by Robert G. Wilson v (rgwv(AT)rgwv.com) 
               and Klaus Brockhaus (klaus-brockhaus(AT)t-online.de), Sep 14 2004
%E A098062 Edited by N. J. A. Sloane (njas(AT)research.att.com), Jul 02 2008 at 
               the suggestion of R. J. Mathar

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