Search: id:A098727 Results 1-1 of 1 results found. %I A098727 %S A098727 2,4,6,8,10,12,14,16,18,11,11,13,14,15,17,17,20,19,23,21,26,23,29,25,32, %T A098727 27,35,29,38,32,31,34,34,36,37,38,40,40,43,42,46,44,49,46,52,48,55,50, %U A098727 58,53,51,55,54,57,57,59,60,61,63,63,66,65,69,67,72,69,75,71,78,74,71 %N A098727 Consider the sequence {b(n), n >= 1} of digits of the natural (or counting) numbers: 1 2 3 4 5 6 7 8 9 1 0 1 1 1 2 1 3 1 4 1 5 1 6 1 7 1 8 1 9 2 0... (A007376); a(n) = b(n) + n. %C A098727 Add each digit of the counting numbers to its rank. %e A098727 The sequence of digits of the counting numbers is %e A098727 1 2 3 4 5 6 7 8 9 1 0 1 1 1 2 1 3 1 4 1 5 1 6 1 7 1 8 1 9 2 0... %e A098727 The 15th term, for instance, is a 2. Thus 2+15=17 is the 15th term of this sequence. %Y A098727 Cf. A007376, A033307, A098728, A098729, A098732, A098733, A098734. %Y A098727 Sequence in context: A061762 A136614 A097586 this_sequence A095815 A063114 A064806 %Y A098727 Adjacent sequences: A098724 A098725 A098726 this_sequence A098728 A098729 A098730 %K A098727 base,easy,nonn %O A098727 1,1 %A A098727 Alexandre Wajnberg (alexandre.wajnberg(AT)ulb.ac.be), Sep 30 2004 %E A098727 More terms from Joshua Zucker (joshua.zucker(AT)stanfordalumni.org), May 18 2006 Search completed in 0.001 seconds