|
Search: id:A098727
|
|
|
| A098727 |
|
Consider the sequence {b(n), n >= 1} of digits of the natural (or counting) numbers: 1 2 3 4 5 6 7 8 9 1 0 1 1 1 2 1 3 1 4 1 5 1 6 1 7 1 8 1 9 2 0... (A007376); a(n) = b(n) + n. |
|
+0 4
|
|
| 2, 4, 6, 8, 10, 12, 14, 16, 18, 11, 11, 13, 14, 15, 17, 17, 20, 19, 23, 21, 26, 23, 29, 25, 32, 27, 35, 29, 38, 32, 31, 34, 34, 36, 37, 38, 40, 40, 43, 42, 46, 44, 49, 46, 52, 48, 55, 50, 58, 53, 51, 55, 54, 57, 57, 59, 60, 61, 63, 63, 66, 65, 69, 67, 72, 69, 75, 71, 78, 74, 71
(list; graph; listen)
|
|
|
OFFSET
|
1,1
|
|
|
COMMENT
|
Add each digit of the counting numbers to its rank.
|
|
EXAMPLE
|
The sequence of digits of the counting numbers is
1 2 3 4 5 6 7 8 9 1 0 1 1 1 2 1 3 1 4 1 5 1 6 1 7 1 8 1 9 2 0...
The 15th term, for instance, is a 2. Thus 2+15=17 is the 15th term of this sequence.
|
|
CROSSREFS
|
Cf. A007376, A033307, A098728, A098729, A098732, A098733, A098734.
Sequence in context: A061762 A136614 A097586 this_sequence A095815 A063114 A064806
Adjacent sequences: A098724 A098725 A098726 this_sequence A098728 A098729 A098730
|
|
KEYWORD
|
base,easy,nonn
|
|
AUTHOR
|
Alexandre Wajnberg (alexandre.wajnberg(AT)ulb.ac.be), Sep 30 2004
|
|
EXTENSIONS
|
More terms from Joshua Zucker (joshua.zucker(AT)stanfordalumni.org), May 18 2006
|
|
|
Search completed in 0.002 seconds
|