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Search: id:A099376
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| A099376 |
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An inverse Chebyshev transform of x^3. |
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+0 1
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| 0, 1, 4, 14, 48, 165, 572, 2002, 7072, 25194, 90440, 326876, 1188640, 4345965, 15967980, 58929450, 218349120, 811985790, 3029594040, 11338026180, 42550029600, 160094486370, 603784920024, 2282138106804, 8643460269248
(list; graph; listen)
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OFFSET
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0,3
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COMMENT
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The sequence is 0,0,0,1,0,4,0,14,0,...with zeros restored. Second binomial transform of (-1)^n*A003518(n). Second binomial transform of expansion of x^3c(-x)^8, where c(x) is g.f. of A000108. The g.f. is transformed to x^3 under the Chebyshev transformation A(x)->(1/(1+x^2))A(x/(1+x^2)). For a sequence b(n), this corresponds to taking sum{k=0..floor(n/2), C(n-k,k)(-1)^k*b(n-2k)}, or sum{k=0..n, C((n+k)/2,k)b(k)(-1)^((n-k)/2)(1+(-1)^(n-k))/2}.
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FORMULA
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G.f.: (1-2x)^4(sqrt((1+2x)/(1-2x))-1)^8/(256x^5); a(n)=sum{k=0..n, (k+1)C(n, (n-k)/2)(-1)^k(C(3, k)-3C(2, k)+3C(1, k)-C(0, k))(1+(-1)^(n-k))/(n+k+2)}.
a(n)=A002057(n-1). - Michael Somos Jul 31 2005
Given an ellipse with eccentricity e and major and minor axis a and b respectively, then ((a-b)/ (a+b))^2 = 1*(e/2)^4 +4*(e/2)^6 +14*(e/2)^8 +48*(e/2)^10 +... - Michael Somos Apr 11 2007
E.g.f.: exp(2x)(Bessel_I(1,2x)-Bessel_I(3,2x)); - Paul Barry (pbarry(AT)wit.ie), Jun 04 2007
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PROGRAM
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(PARI) {a(n)= if(n<1, 0, n++; 2* binomial(2*n, n-2)/n)} /* Michael Somos Apr 11 2007 */
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CROSSREFS
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Cf. A003518, A000245.
Sequence in context: A094827 A094667 A002057 this_sequence A047048 A071745 A071749
Adjacent sequences: A099373 A099374 A099375 this_sequence A099377 A099378 A099379
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KEYWORD
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easy,nonn
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AUTHOR
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Paul Barry (pbarry(AT)wit.ie), Oct 13 2004
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