Search: id:A101859
Results 1-1 of 1 results found.

%I A101859
%S A101859 0,11,23,36,50,65,81,98,116,135,155,176,198,221,245,270,296,323,351,380,
%T A101859 410,441,473,506,540,575,611,648,686,725,765,806,848,891,935,980,1026,
               1073,
%U A101859 1121,1170,1220,1271,1323,1376,1430,1485,1541,1598,1656,1715,1775,1836
%N A101859 a(n) = 11 + (23*n)/2 + n^2/2.
%C A101859 a(n)=A000096 + 9 * A001477 and a(n)=A056126 + A001477. - Zerinvary Lajos 
               (zerinvarylajos(AT)yahoo.com), Oct 01 2006
%C A101859 a(n) = A126890(n+1,10) for n>8. - Reinhard Zumkeller (reinhard.zumkeller(AT)gmail.com), 
               Dec 30 2006
%H A101859 C. Rossiter, <a href="http://noticingnumbers.net/300SeriesCube.htm">Depictions, 
               Explorations and Formulas of the Euler/Pascal Cube</a>.
%F A101859 a(n)=C(n,2)-10*n,n>=21 - Zerinvary Lajos (zerinvarylajos(AT)yahoo.com), 
               Nov 26 2006
%F A101859 G.f.: (11-10x)/(1-x)^3. [From R. J. Mathar (mathar(AT)strw.leidenuniv.nl), 
               Sep 09 2008]
%F A101859 If we define f(n,i,a)=sum(binomial(n,k)*stirling1(n-k,i)*product(-a-j,
               j=0..k-1),k=0..n-i), then a(n-1) = -f(n,n-1,11), for n>=1. [From 
               Milan R. Janjic (agnus(AT)blic.net), Dec 20 2008]
%F A101859 a(n)=n+a(n-1)+9 (with a(1)=0) [From Vincenzo Librandi (vincenzo.librandi(AT)tin.it), 
               Nov 19 2009]
%e A101859 For n=2, a(2)=2+0+9=11; n=3, a(3)=3+11+9=23; n=4, a(4)=4+23+9=36 [From 
               Vincenzo Librandi (vincenzo.librandi(AT)tin.it), Nov 19 2009]
%p A101859 a:=n->sum(floor(k+2*n/(k+n)), k=10..n): seq(a(n),n=10..57); - Zerinvary 
               Lajos (zerinvarylajos(AT)yahoo.com), Oct 01 2006
%p A101859 [seq(binomial(n,2)-10*n,n=21..72)]; - Zerinvary Lajos (zerinvarylajos(AT)yahoo.com), 
               Nov 26 2006
%p A101859 a:=n->sum(numer (k/(k+3)), k=11..n): seq(a(n), n=10..61); - Zerinvary 
               Lajos (zerinvarylajos(AT)yahoo.com), May 31 2008
%p A101859 with(finance):seq(add(cashflows([2,k,8], 0 ),k=1..n),n=0..50); - Zerinvary 
               Lajos (zerinvarylajos(AT)yahoo.com), Jun 22 2008
%t A101859 i=-10;s=0;lst={};Do[s+=n+i;If[s>=0, AppendTo[lst, s]], {n, 0, 6!, 1}];
               lst [From Vladimir Orlovsky (4vladimir(AT)gmail.com), Oct 29 2008]
%Y A101859 Cf. A000096, A056126, A001477.
%Y A101859 Sequence in context: A136771 A017653 A139793 this_sequence A079664 A160268 
               A135978
%Y A101859 Adjacent sequences: A101856 A101857 A101858 this_sequence A101860 A101861 
               A101862
%K A101859 easy,nonn,new
%O A101859 -1,2
%A A101859 Cecilia Rossiter (cecilia(AT)noticingnumbers.net), Dec 18 2004
%E A101859 Edited by N. J. A. Sloane (njas(AT)research.att.com), Oct 07 2006

Search completed in 0.001 seconds