|
Search: id:A103242
|
|
|
| A103242 |
|
Non-reduced numerators of the elements T(n,k)/(n-k)!, read by rows, of the triangular matrix P^-1, which is the inverse of the matrix defined by P(n,k) = (1-(k+1)^2)^(n-k)/(n-k)! for n>=k>=1. |
|
+0 2
|
|
| 1, 3, 1, 39, 8, 1, 1206, 176, 15, 1, 69189, 7784, 495, 24, 1, 6416568, 585408, 29430, 1104, 35, 1, 881032059, 67481928, 2791125, 84600, 2135, 48, 1, 168514815360, 11111547520, 389244600, 9841728, 204470, 3744, 63, 1, 42934911510249
(list; table; graph; listen)
|
|
|
OFFSET
|
1,2
|
|
|
COMMENT
|
Define triangular matrix P by P(n,k) = (-k^2-2*k)^(n-k)/(n-k)!, then M = P*D*P^-1 = A103236 satisfies: M^2 + 2*M = SHIFTUP(M) where D is the diagonal matrix consisting of {1,2,3,...}. The operation SHIFTUP(M) shifts each column of M up 1 row. Essentially equal to square array A082171 as a triangular matrix. The first column is A082163 (enumerates acyclic automata with 2 inputs).
|
|
FORMULA
|
For n>k>=1: 0 = Sum_{m=k..n} C(n-k, m-k)*(1-(m+1)^2)^(n-m)*T(m, k). For n>k>=1: 0 = Sum_{j=k..n} C(n-k, j-k)*(1-(k+1)^2)^(j-k)*T(n, j).
|
|
EXAMPLE
|
Rows of non-reduced fractions T(n,k)/(n-k)! begin:
[1/0! ],
[3/1!, 1/0! ],
[39/2!, 8/1!, 1/0! ],
[1206/3!, 176/2!, 15/1!, 1/0! ],
[69189/4!, 7784/3!, 495/2!, 24/1!, 1/0! ],
[6416568/5!, 585408/4!, 29430/3!, 1104/2!, 35/1!, 1/0! ],...
forming the inverse of matrix P where P(n,k)=A103247(n,k)/(n-k)!:
[1/0! ],
[ -3/1!, 1/0! ],
[9/2!, -8/1!, 1/0! ],
[ -27/3!, 64/2!, -15/1!, 1/0! ],
[81/4!, -512/3!, 225/2!, -24/1!, 1/0! ],
[ -243/5!, 4096/4!, -3375/3!, 576/2!, -35/1!, 1/0! ],...
|
|
PROGRAM
|
(PARI) {T(n, k)=local(P); if(n>=k&k>=1, P=matrix(n, n, r, c, if(r>=c, (1-(c+1)^2)^(r-c)/(r-c)!))); return(if(n<k|k<1, 0, (P^-1)[n, k]*(n-k)!))}
|
|
CROSSREFS
|
Cf. A103247, A103236, A082171, A082163.
Sequence in context: A095844 A113110 A109842 this_sequence A050817 A125082 A136517
Adjacent sequences: A103239 A103240 A103241 this_sequence A103243 A103244 A103245
|
|
KEYWORD
|
nonn,tabl,frac
|
|
AUTHOR
|
Paul D. Hanna (pauldhanna(AT)juno.com), Feb 02 2005
|
|
|
Search completed in 0.002 seconds
|